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QUESTION 6 Answer the question on the basis of the following two schedules, which show the amounts of additional satisfaction
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Answer #1

The utility is maximized where MU/P f J is = MU/P of K

It will take 4 units of J and 5 units of K

Units of J MUJ MU/P Units of K MUK MU/P 00 una - 4 324 324 24 34 20 20 2. 5 5 12 16 2 6 10 12 1.5 7 8 6 7 2.5 2

Total Utility from J = 56 + 48 + 32 +24 = 160

Total Utility from K = 32 +28 + 24 + 20 + 12 = 116

Total Utility of both units are = 160 + 116 = 276

Answer is Option D = 276

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