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CH,Br 3H doublet at 2.0 S, J = 7 Hz 1H quartet at 5.0 8. J = 7 Hz 5H singlet at 7.3 8 - CH3 Answer:

could you please help me to explain the problem with answers ?

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Answer #1

1.Aromatic proton will not show same chemical shift because there chemical environment are different.

2. Aromatic proton will not show singlet, because each proton is having neighbouring proton.

3. This molecule is having symmetry so there will be two ortho proton will show same chemical shift and will show doublet similarly meta protons (2 proton) will show same chemical shift with doublet of doublet and para position proton will show different chemical shift.

4. So there will 3 different kinds of proton peak instead of one.

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