Question

the avg k is 0.016. How do I answer part 3?

Question 5 Here are your data from Part C: The Effect of Temperature Room temperature Temperature of ice bath Slope of best fit line 296 K. 274 K -0.001700 Part 1: What is the numerical value of the apparent rate constant at the colder temperature, kes of the reaction? 1.700x10-3 Ok Ok Part 2: Solve for the numerical value of kc given that ke' = ke[OH-]" = k[0.30]? 5.6x10-3 Ok Part 3: Solve for the activation energy of the reaction using the average value of k for this reaction at room temperature and the value of kc at the lower temperature that you previously calculated. 35.40 kJ/mol Submit

Answer 1

(3) from Arrhenius Equation, Ko A e Ea/R17 e Constant Kon rate constant to activation energy Universal Gor Temperature - I do K = ln A - Ea Al room demp (996x), K = 0.016 1 296W| At 274 K temp, stane 25.6810 3 11 7 2 2 274K) do Ky a lon A - Ea .... 0 In Ky low-to--- La let) - (-) RT, Bila Knowo, Le 8.314 32" moot"] cha (6460) - Cape ) Y 1.049 .-ta (-0.0009-11) 8.314 1 af faa 1.049 x 8.314 32182.24 I moth 0.000271 ta 32182 24 Jmol. 32.18 KJ/mo)