Answer 1: The name of the reaction is Robinson Annulation named after Robert Robinson. it is used to create cyclic compound by forming C-C bond. Basically it involves Michael addition (1,4-addition) followed by intramolecular aldol condensation to give the final product. As shown in the figure the substrate after formation of enolate ion undergo Michael addition reaction which gives intermediate (I) which tautomerizes to (II). In the presence of base it gives another enolate ion (III) which undergo aldol codensation to give (IV). This is followed by dehydration with removal of water molecule to give the final product.
Propose a detailed mechanism for the following transformation. Use curved arrows to show movement of electron...
First box is to add in curved arrows that illustrate the first step of this mechanism. Second box is Draw the two intermediates that form and show curved arrows depicting the next step. Third is Draw the intermediate and the small molecule with which it will react. Show curved arrows depicting the next step. Fourth box is Draw the intermediate and the small molecule with which it will react. Show curved arrows depicting the next step. 05 Question (1 point)...
1) Propose a mechanism for the following two-step transformation. Be sure to include all curved arrows, intermediates, and by-products. (5 marks) Br -OH Br 1) NaOH, HÀO 2) HBO ОН
1-Propose a mechanism for the following reaction using curved arrows to show electron movement. (5 Marks) Br HBr Br
1) Propose a mechanism for the following two-step transformation. Be sure to include all curved arrows, intermediates, and by-products. (5 marks) Br -OH 1) NaOH, HO 2) HBO Br OH 2) Propose a synthesis for the transformation below. You may use any reagent discussed in the course notes or textbook, as well as any additional compound with 2 or fewer C atoms in your solution. (5 marks) هر
4 and 5 PLEASE HELP curved arrows to indicate electron movement for each step. Draw all the resonance structures of the sigma complex intermediate. 4. (6 pts) a) Draw the complete mechanism to account for the following reaction. Make sure to show OCH3 Ords CI AICI 5. (6 pts) Draw the step-by-step mechanism for the reaction below, using curved arrows to show the flow of electrons and draw any resonance intermediates. Br Bг NO2 HNO3 H2SO4
2. (6 pt) For each reaction, draw the correct curved arrows showing electrons movements (electron pushing), and show the missing lone pairs. Name each step (e.g., coordination, Nu attack, etc.) and name overall mechanism for each reaction (e.g., elimination, etc.) o ni. + CN ne grow. OCH — Oro. Cho OCH + OCH3 + CH3OH
28. Refresh from practice worksheet, propose a mechanism using curved arrows to show electron movement for each step. CH2CH=CH2 + HBr – CH3CH(Br)CH3
Electrophilic addition of bromine, Br-, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH2Cl2 In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product...
Electrophilic addition of bromine, Br2, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH2Cl2 In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product...
10. Provide a detailed mechanism for the following transformation. Be sure to use curved arrows, correct reaction arrows, Show all relevant lone pairs and bonds, formal charges and all intermediates. Think about what your components are and what would happen first. (5 points) HBr Me on me mé Br + Ho Me