Question

Due Sun 11/10/2019 11:59 pm Show Intro/Instructions Today, the waves are crashing onto the beach every 5 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 5 seconds. Round to 4 decimal places where possible. a. The mean of this distribution is b. The standard deviation is c. The probability that wave will crash onto the beach exactly 2.4 seconds after the person arrives is P(x = 2.4) = d. The probability that the wave will crash onto the beach between 14 and 3.5 seconds after the person arrives is P(1.4 <x< 3,5) = e. The probability that it will take longer than 39 seconds for the wave to crash onto the beach after the person arrives is P(x > 3.9) = f. Find the minimum for the upper quartile. seconds. Get help: Video Video Written Example Points possible: 6 Unlimited attempts. Message instructor about this question Submit

Answer 1

In this Today, the waves are crashing onto the beach every 5 seconds. The time from when a person arrives at the shoreline until a crashing wave is observed follows a uniform distribution from o to 5 Seconds. azo ; b=5 2.) The mean of the distribution is M = ato -075 = 2.5 6.) The Standard deviation is -146033 (5ogle = {1-44134 (2 2- f: P(x=x) =%-a] X-X 7 P(1.4 cx <3.5) - 5-0 P( x < x < x ) C.) The probability that wave will crash onto the beach exactly 2:4 Seconds after the person arrives is PCX =24) PLX=204) = 240 P(x = 2.4) - ID:48oo. d) The probability that the wave will crashonto the beach between 104 and 35 seconds after the person arrives 's PC 1.42 X< 3:5) - 3.5-1.4 Sip(x, < X < X 2) = bal -04200 e.) The probability that it will take longer than 3.9 Seconds for the wave to crash onto the beach after the person arrives is p(x>3.9) P(x>3.9) = 5-3.9 -10.2200) [":PL *>x) = brz? 5-0 I find the minimum for the upper quartile - seconds. PEx>03] = 0.25 12 = 0.25 Ś (5-3) = 0.25 +1-23 = 0.25 23 = 3.75