Question

Refer to the data set of body temperatures in degrees Fahrenheit given in the accompanying table and use software or a calculator to find the mean and median. Do the results support or contradict the common belief that the mean body temperature is 98.6 F? Click the icon for the body temperature data. The mean of the data set isF. Round to two decimall places as needed Body Temperatures 99.2 99.2 98.2 98.0 97.8 97.1 97.9 98.7 98.7 98.8 98.4 97.7 97.6 99.3 99.3 97.6 99.3 976 994 98.9 98.5 97.5 996 98.5 994 98.5 98.8 98.2 97.4 98.0 978 98.0 96.8 96.6 97.5 97.5 98.1 98.8 97.8 98.3 99.0 98.1 98.7 98.9 98.3 96.6 974 97.7 PrintDone Enter your answer in the answer box and then click Check Answer Clear Al Check Answer remainino avascriot:doExercise 6)

Answer 1

The body temperature data in Fahrenheit is given as follows: 99.2 99.2 98.2 98.0 97.8 97.6 99.3 99.3 976 99.3 99.4 98.5 98.8 98.2 97.4 98.1 98.8 978 98.3 99.0 97.1 97.9 98.7 97.6 99.4 98.9 98.0 978 98.0 98.1 98.7 98.9 98.7 98.8 98.5 97.5 96.8 96.6 98.3 96.6 98.4 99.6 97.5 97.4 97.7 98.5 97.5 97.7 The mean and median are calculated using R is given below: 1. First create a variable name "Temp" and store the data in the "Temp" as given below: Temp c(99.2.99.2.98.2.98.97.8.97.1,97.9,98.7.98.7.98.8.98.4,97.7.97.6,99.3,99.3,97.6,99.3,97.6, 99.4,98.9,98.5,97.5,99.6,98.5,99.4,98.5,98.8.98.2.97.4,98,97.8,98,96.8,96.6.97.5.97.5.98. 1,98.8.97.8.98.3,99.98.1,98.7.98.9,98.3,96.6,97.4,97.7) Temp Run the code and the output is given below: > Temp [1] 99.2 99.2 98.2 98.0 97.8 97.1 97.9 98.7 98.7 98.8 98.4 97.7 97.6 99.3 99.3 [16] 97.6 99.3 97.6 99.4 98.9 98.5 97.5 99.6 98.5 99.4 98.5 98.8 98.2 97.4 98.0 [31] 97.8 98.0 96.8 96.6 97.5 97.5 98.1 98.8 97.8 98.3 99.0 98.1 98.7 98.9 98.3 [46] 96.6 97.4 97.7 2. Use the mean() function to calculate the mean of the data given below: > mean (Temp) [1] 98.22917 3. Use the median() function to calculate the median of the data given below: > median (Temp) [1] 98.2