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5, + 0/16.66 points l Previous Answers ASWSBE 1312. E.025 My Notes Ask Your Teacher You may need to use the appropriate technology to answer this question. Use α = 0.01 and conduct a goodness of fit test using 5 classes to see whether the following sample appears to have been selected from a normal probability distribution. (Note: x 71.4 and s 17.) 55 86 94 5855 95 55 52 6995 90 65 87 5056 55 57 98 5879 92 62 59 88 75 State the null and alternative hypotheses O Ho: The population has a normal probability distribution Ha: The population has a sampling mean distribution O Ho: The population has a normal probability distribution Ha: The population has a x2 distribution Ho: The population does not have a normal probability distribution Ha: The population has a normal probability distribution Ho: The population has a normal probability distribution Ha: The population does not have a normal probability distribution Find the value of the test statistic 20.4 Find the p-value. (Round your answer to four decimal places.) p-value0.0004 State your conclusion Reject Ho. We conclude that the population does not have a normal probability distribution Reject H. We conclude that the population has a normal probability distribution O Do not reject Ho. We conclude that the population does not have a normal probability distribution O Do not reject Ho. We conclude that the population has a normal probability distributionConstruct a histogram of the data 15 15 0 80 100 20 40 60 80 100 20 40 60 Percentage of Data Percentage of Data 15 15 20 40 60 80 100 0 40 60 80 100 Percentage of Data 20 Percentage of Data Does the histogram representation support the conclusion reached with the goodness of fit test? Yes, the histogram representation supports the conclusion reached with the goodness of fit test. No, the histogram representation does not support the conclusion reached with the goodness of fit test

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Answer #1
x
50
52
55
55
55
55
56
57
58
58
59
62
65
69
75
79
86
87
88
90
92
94
95
95
98
Class Interval Observed f Expected frequency (as per normal distribution) (Observed - Expected)^2 /Expected
< 50 0 2.601175995 2.601175995
50-60 11 3.679859995 14.56154575
60-70 3 5.398539714 1.065657208
70-80 2 5.658683778 2.365561942
80-90 3 4.237948221 0.361617396
90-98 6 1.953143689 8.384967321
>= 98 0 1.470648607 1.470648607
chi-square value = 30.81117422
Hypotheses:
Ho: The population has a normal distribution
Ha: The population does not have a normal distribution
(Option D)
Test statistic = 30.81
DOF = 7 - 1 = 6
p- value = 0.0000
Conclusion: Reject Ho. The data does not seem to come from a normal distribution (Option A)
Graph: Option (D)
Yes, the histogram supports the conclusion (Option (A))
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