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For the hydrogen atom, the transition from the 2p state to the is state is accompanied by the emission of a photon with an en

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Answer #1

Answer -

Given,

Transition levels

n final = 1s

n initial = 2p

Energy for the transition of H from 2p to 1s = 16.2 * 10-19 J

wavelength in Case of Cl in these states = 4.73 A

Energy Difference for Chlorine from 2p to 1s = ?

We know that,

E = hc/\lambda

where, E = Energy

h = planks constant (6.62607015×10−34 Js)

c = Speed of light (3 * 108 m/s)

\lambda = wavelength

Also, 1A = 10-10 m

So, 4.73 A = 4.73 * 10-10 m

Put values in formula,

E = (6.62607015×10−34 Js * 3 * 108 m/s) /4.73 * 10-10 m

Energy difference between these states of Cl = 42.02 * 10-17 J [ANSWER]

Energy Difference of H atom = 0.162 * 10-17 J

Energy Difference of Cl atom = 42.02 * 10-17 J

Difference in energy differences of Cl and H = (42.02 - 0.162) * 10-17 J = 41.858* 10-17 J

So,The energy differences between these state in chlorine is Greater (Greater by 41.858* 10-17 J) than the corresponding energy difference hydrogen [ANSWER]

Now,

According to Rydberg's Equation,

1/\lambda = RZ2 {[1/(nf)2] - [1/(ni)2]}

where \lambda = wavelength in m

R = 1.097x 107 m-1

Z = atomic Number

nf and ni are energy levels

For, Chromium

1/\lambda = 1.097x 107 m-1 * (242) {[1/(1)2] - [1/(2)2]}

\lambda = 2.11 * 10-10 m

Also, E = hc/\lambda

where, E = Energy

h = planks constant (6.62607015×10−34 Js)

c = Speed of light (3 * 108 m/s)

\lambda = wavelength

Put values in formula,

E = (6.62607015×10−34 Js * 3 * 108 m/s) / 2.11 * 10-10 m

Energy difference between these states of Chromium = 9.459 * 10-16 J

Energy Difference of Cr atom = 94.59 * 10-17 J

Energy Difference of Cl atom = 42.02 * 10-17 J

Difference in energy differences of Cr and Cl = (94.59 - 42.02) * 10-17 J = 52.57* 10-17 J

So,The energy differences between these state in chromium is Greater (Greater by 52.57* 10-17 J) than the corresponding energy difference hydrogen [ANSWER]

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