Question

A hydrogen atom in a state having a binding energy (the energy required to remove an electron) of -0.850 eV makes a transition to a state with an excitation energy (the difference between the energy of the state and that of the ground state) of 12.089 eV. (a) What is the energy of the photon emitted as a result of the transition? What are the (b) higher quantum number and (c) lower quantum number of the transition producing this emission? Use -13.60 eV as the binding energy of an electron in the ground state.

Answer 1

ct The energy of the higher state is E20.85 eV The energy of the lower state is, E 12.089-13.6 eV1.511 eV The energy of the photon emittedis, E E2-0.85-(1.511 eV)-0.661 eV The energy of the higher state is E--0.85 eV -13.6 0.85 eV 72 Solve for n The energy of the lower state is, E 1.511 eV 13.6 ,2-=-1.511 eV Solve for n