Question

Pre-Lab Assignment, consider the ing no water) alum. Slab, you will perform the synthesis of hydrated alum [KAl(SO): 12 Assignment, consider the net reaction for the synthesis of anhydrous sis of hydrated alum [KAISOJ, 12H,0). For this 1. Balance the following equation: AI(S) + 4H,SO,(aq) +_ KOH(aq) - KAI(SO).(s) + _ 2. Calculate the molar mass of anhydrous'alum [KAl(SO).. H,001) +3H:18) 3258:192 3. If the sulfuric acid (H,SO,) and potassium hydroxide (KOH) are in excess, how many grams of anhydrous alum are formed from 22.00 g of Al(s)? This calculated value is the theoretical yield. 4. If the reaction in Question 3 is carried out, the actual recovery of KAl(SO) is 154.3 g. What is the percent recovery of anhydrous alum? Use Equation (8).

Answer 1

1) The balanced reaction is:

2 Al + 4 H2SO4 + 2 KOH = 2 KAl (SO4) 2 + 2 H2O + 3 H2

2) The molar weight of the anhydrous is 258.19 g / mol.

3) The mass of anhydrous formed is calculated:

m anhydrous = 22 g Al * (1 mol Al / 27 g) * (2 mol anhydrous / 2 mol Al) * (258.19 g anhydrous / 1 mol) = 210.4 g

4) The recovery percentage is calculated:

% yield = 154.3 * 100 / 210.4 = 73.33%

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