Question

ander is the mass of the FROM THE CYLINDER the identity of the metal CYLINDER Untie as many knots as possible in the monofilament line and return the line to the instructor Identity of metal Mass of metal, (g) Zinc 33.69 Trial 1 Trial 2 4.65 Mass of Styrofoam cup and water, Mass of Styrofoam cup, () Mass of water, (g) Thitin temperature of metal Temperature or die boiling water) al temperature or water in Finaal temperature of water and me Specifichent of metall Average specific heal of metal, (cal/g C) 58.5. 58.5. 4.65. 53.85 153, S. 75 73" 22°C 2.7C2 .5C m Calculations: AT water - Ti-Ti water ATmetal "Tr-Timetal -__ - °C Qwater - (1.00 calg°C)x( 8H20)x( °C)- Ce Qual/ MX A c al/ Show your calculation for the second trial below. cal Ometal -- Owater "C _ cal/gC 2

Answer 1

The specific heat and other calculations for the second trial can be found by using various formulaes.

SOLUTION: Calculations for the second trial are as shown: GIVEN! FOR TRIAL 2 Initial temperature of water (T;) = 23°C. final temperature of water (Tp) = 25c. Initial temperature of metal (Ti) = 73°c. Final temperature of metal (Tf) = 25°C Mass of water = 53.85g.. Mass of Metal (Mmetal)- 33.692. using the above data we can do all the calculations: 1) Al water - Tf - Ti water - 25%-23 e = 12c] 2) AT metal =Tr-Ti metal = 25°c - 73 c = (-48°c) 3) Pwater = (1.00cally c)x(Mwater g) x( °c). - (1.00 calq°c) (5385 g 40x12°c). E Qwater = 107. I cal Q metal = - Qwater Q metal = -107, 7 call. (4) Cmetal Ametall Metal ATmetal. = -107.7 cal) [(33.69)+(-48°c)] = (-107.4 cal)/C-1612-8] : Cmetal = 0.067 callge! I