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Report: Specific Heat Capacity nctal ideatity Alunminum mas of metal 824 OLT mas of water884 4895 414. 3 metal intia emperatu


Report: Specific Heat Capacity metal identity mass of metal mass of water 3 metal initial temperature preperiod slope .0054 0 calculating the Qwater, Qmetal, specific heat capacity of metal, molar mass metal, molar heat capacity metal, and relative error.
Report: Specific Heat Capacity nctal ideatity Alunminum mas of metal 824 OLT mas of water884 4895 414. 3 metal intia emperature 25 lalao0 25380 25350 oreperiod tope O.0054 0.0049 .Oos eriod intercept 3 18138 5.3939 Col o07 postperiod slope G. OOSI | pospertod nerep: 4.8210 8.3648 81513 half way time(2.5s lol 3 a2.4 ater 513 5.64347894 postperiod intercept water initial temperature. · 1つ1 final temperature ATwater 51884s/ 2.90S1 / I '94644 ATmetal 15.125-16.18 23.4oSl Q metal specific heat capacity metal molar mass metal molar heat capacity metal relative error Use correct units. This sheet should be the first page of the report. Attach graphs forall runs. Place the graphs in the same order as the information in the table above. Graphs should be attached face-up and should read from the bottom or the right. The staple should go in the top left of this sheet. 65
Report: Specific Heat Capacity metal identity mass of metal mass of water 3 metal initial temperature preperiod slope .0054 0.0044 .OOS preperiod intercopt 3.18138 5.3439lel7 pospetod sope 0051 0.00 0.0042 porptidy 1.8210 8.3648 .1513 half-way time 35 water initial er ta teratue4.1513 5.443 (47894 final temperature AT water 5.48845 2.905 1.94644 9:mxCx Q water AT metal Q metal specific heat capacity metal molar mass metal molar heat capacity metal relative error Use correct units. This sheet should be the first page of the report. Attach graphs forall runs. Place the graphs in the same order as the information in the table above. Graphs should be attached face-up and should read from the bottom or the right. The staple should go in the top left of this sheet. 65
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Answer #1

A)

  • In case of Al

Q water = mass (in g) x specific heat capacity (in J/g 0C ) x Change in temperature (o C )

= 39.88 g x 4.184 J/g 0C x 5.98845 oC = 999.2203 J

  • In case of Copper

Qwater = 48.95 g x 4.184 J/goC x 2.9057 oC =595.1071 J

  • In case of Tin

Qwater = 44.16g x 4.184 J/goC x 1.94044 oC = 358.536 J

B) Specific heat capacity

Specific heat capacity of Al = 0.900 J/g 0C

Specific heat capacity of copper = 0.385  J/g 0C

Specific heat capacity of tin = 0.21  J/g 0C

C) molar mass of metals

Molar mass of Al = 26.98 u

Molar mass of Copper = 63.546 u

Molar mass of tin = 118.71 u

D) Relative error = Absolute error / actual error

Absolute errror can be obtained by , absolute error = estimated value /real value

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