Question

Date Name Lab Instructor Experiment 8-Gas Laws Prelaboratory Exercises 1. Fill in the blanks in a through d. d. As the pressure on a sample of a gas increnses al constant temperature, the volume of the gask .ease in c 's law. b. As the number of moles of a gas increases at constant pressure and temperature, the volume of the gas increases in Macodro's law. c. The volume of a sample of hydrogen gas at STP is 1.00 liter. As the tempera ure decreases, at constant pressure, the volume of the sample decrease in Charles law. pressure of the d. As the temperature of a sample gas increases at constant volume, the pres gas sample sease in Gay-Lusso c Slaw. For questions 2–4 show all calculations. 2. A 100-milliliter sample of a gas at a pressure of 380. torr is reduced to 190. torr at con- stant temperature. What is the new volume of the gas? 3. At constant pressure. 8.0 liters of a gas is heated from 25.5°C to 50°C. What is the new volume of the gas? 4. At constant volume, the temperature of 2.0 atm of gas was 325 K. The temperature is increased to 400 K. What is the new pressure of the gas?

Answer 1

Q2:

According to Boyle's law P₁V₁ = P₂V₂

Here in the question P1 = 100 ml, V1 = 380 torr

P2 = 180 torr and V2 = to be calculated

So according to the equation, V2 =(P1 V1) / V2

V2 = (100 ml X 380 torr) / 190 torr = 200 ml

The answer is 200 ml

Q3:

According to Charle's law at Constant pressure V / T = Constant or in other words V₁/T₁ = V₂/ T₂

V1 = 8 liter T1 = 25.5 C (298.6 K)

T2 = 50 C (323.1), V2 unknown

According to equation V2 = (V1 X T2)/ T1 = (8.0 L X 323.1 K) / 298.6 K = 8.65 L

Answer is 8.65 L

Q4:

According to Gay- Lussacs Law P / T = Constant or in other words P₁/T₁ = P₂/ T₂

Here in the question P₁ = 2.0 atm, T₁ = 325 K and T2 = 400 K, P₂ is unknown

So according to the eqauation

P₂ =(P₁ X T₂ )/T₁ = (2.0 atm X 400 K) / 325 K = 2.46 atm

Answer is 2.46 atm