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10- A 67 g aluminum spoon (specific heat 0.88 J/g°C) at 22°C is placed in 237...

10- A 67 g aluminum spoon (specific heat 0.88 J/g°C) at 22°C is placed in 237 mL (237 g) of coffee at 90°C and the temperature of the two become equal after a time. What is the final temperature when the two become equal? Assume that coffee has the same specific heat as water (Cs =4.184 J/g°C).

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Answer #1

Heat released by Coffee = Heat absorbed by boom. > (237)(4:184)/90-1) = 61)(0.88)(mp-22) Let If is final temperature for both

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