Part A:
Suppose you work for a pharmaceutical company that is testing a new drug to treat ulcerative colitis. You conduct a random sample of 34 patients on the new drug and 14 of them indicated a decrease in symptoms since starting the drug regimen. You construct a 90% confidence interval for this proportion to be ( 0.2733 , 0.5502 ). What is the correct interpretation of this confidence interval?
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Part B:
A company seeks to employ a new public relations manager. The hiring committee surveys 15 public relations managers and finds the average salary is $95157.334 with standard deviation of $1895.2408. What is the 95% confidence interval for the true average public relations manager salary?
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Part C:
You read an article in Golf Digest that someone with your average drive distance will have an average score of 84.71. You keep track of your scores for the next 10 rounds and see that your average score is 76.81 with a standard deviation of 2.939 strokes. You create a 90% confidence interval for your average score and it is (75.11, 78.51). Given this information, what is the best conclusion?
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Part D
A pharmaceutical company is testing a new drug to increase memorization ability. It takes a sample of individuals and splits them randomly into two groups. One group is administered the drug, and the other is given a placebo. After the drug regimen is completed, all members of the study are given a test for memorization ability with higher scores representing a better ability to memorize. You are presented a 95% confidence interval for the difference in population mean scores (with drug - without drug) of (0.5, 11.26). What can you conclude from this interval?
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A)
option 3 is correct:
We are 90% confident that the proportion of all patients on the drug regimen that have experienced a reduction in symptoms is between 0.2733 and 0.5502. |
B)
option 5 is correct
C)
option 2 is correct
We are 90% confident that your average score is less than 84.71.
D)option 2 is correct (as CI contains only positive values
We are 95% confident that the average memorization ability of those on the drug is higher than those who are not on the drug.
Part A: Suppose you work for a pharmaceutical company that is testing a new drug to...
You work for a pharmaceutical company that is testing a new cholesterol drug. The proportion of patients on the previous drug who had a positive treatment was 0.375. You want to see if the new drug is more effective than the previous drug. You conduct a sample of 113 patients on the new drug and find that 76 have had a positive treatment effect. The 95% confidence interval is ( 0.586 , 0.7591 ). What is the best conclusion you...
A local pizza place claims that they average a delivery time of 10.14 minutes. To test this claim, you order 13 pizzas over the next month at random times on random days of the week. You calculate that the average delivery time is 8.59 minutes with a standard deviation of 1.721 minutes. You create a 99% confidence interval of (7.13, 10.05). Of those listed below, what is the best conclusion you can make? Question 7 options: 1) The percentage of...
You are curious about the average number of yards Matthew Stafford throws for each game for the Detroit Lions. You randomly select 23 games and see that the average yards per game is 344.5 with a standard deviation of 27.8 yards. You want to create a 95% confidence interval for the true average number of yards per game he throws. What is the margin of error for this estimate? Question 1 options: 1) 1.5833 2) 5.7967 3) 12.0216 4) 9.9538...
1.) Automobile manufacturers are interested in the difference in reaction times for drivers reacting to traditional incandescent lights and to LED lights. A sample of 19 drivers are told to press a button as soon as they see a light flash in front of them and the reaction time was measured in milliseconds. Each driver was shown each type of light. A 90% confidence interval for the average difference between the two reaction times (traditional - LED) was (-306.28, -50.17)....
The Student Recreation Center wanted to determine what sort of physical activity was preferred by students. In a survey of 95 students, 62 indicated that they preferred outdoor exercise over exercising in a gym. When estimating the proportion of all students at the university who prefer outdoor exercise with 99% confidence, what is the margin of error? Question 4 options: 1) 0.1260 2) 0.0062 3) 0.0489 4) 0.0129 5) 0.1138 Question 5 (1 point) Suppose you work for a pharmaceutical...
A pharmaceutical company is testing a new drug to increase memorization ability. It takes a sample of individuals and splits them randomly into two groups: group 1 takes the drug, group 2 takes a placebo. After the drug regimen is completed, all members of the study are given a test for memorization ability with higher scores representing a better ability to memorize. Those 29 participants on the drug had an average test score of 27.92 (SD = 3.215) while those...
A new drug to treat high cholesterol is being tested by pharmaceutical company. The cholesterol levels for 18 patients were recorded before administering the drug and after. The mean difference in total cholesterol levels (after - before) was -8.603 mg/dL with a standard deviation of 5.449 mg/dL. When creating a 90% confidence interval for the true average difference in cholesterol levels by the drug, what is the margin of error? 1) 1.7087 2) 2.2271 3) 2.2342 4) 1.2843 5) 2.1127...
A new drug to treat high cholesterol is being tested by pharmaceutical company. The cholesterol levels for 21 patients were recorded before administering the drug and after. The 90% confidence interval for the true mean difference in total cholesterol levels (after - before) was (14.93, 45.35). Which of the following is the appropriate conclusion? 1) We are 90% confident that the average difference in cholesterol levels is positive, with the higher cholesterol levels being after the drug regimen. 2) We...
In a group of 15 young professionals studied, it was found that they purchased on average $186.498 per month eating meals prepared outside the home, with a standard deviation of $30.392. What is the 99% confidence interval of the true amount of money young professionals spend monthly on meals prepared outside the home? 1) ( 163.138 , 209.858 ) 2) ( 183.521 , 189.475 ) 3) ( 163.372 , 209.624 ) 4) ( -163.138 , 209.858 ) 5) ( 178.651...
As part of a research program for a new cholesterol drug, a pharmaceutical company would like to investigate the relationship between the ages and LDL (low-density lipoprotein) cholesterol of men. The following data set shows the ages and LDL cholesterol levels of seven randomly selected men. Construct a 95% confidence interval to estimate the average LDL cholesterol level of a 31-year-old man. Click the icon to view the datatable Determine the upper and lower limits of the confidence interval UCL-...