Question

The Student Recreation Center wanted to determine what sort of physical activity was preferred by students. In a survey...

The Student Recreation Center wanted to determine what sort of physical activity was preferred by students. In a survey of 95 students, 62 indicated that they preferred outdoor exercise over exercising in a gym. When estimating the proportion of all students at the university who prefer outdoor exercise with 99% confidence, what is the margin of error?

Question 4 options:

1)

0.1260

2)

0.0062

3)

0.0489

4)

0.0129

5)

0.1138

Question 5 (1 point)

Suppose you work for a pharmaceutical company that is testing a new drug to treat ulcerative colitis. You conduct a random sample of 28 patients on the new drug and 10 of them indicated a decrease in symptoms since starting the drug regimen. You construct a 95% confidence interval for this proportion to be ( 0.1797 , 0.5346 ). What is the correct interpretation of this confidence interval?

Question 5 options:

1)

We are 95% confident that the proportion of patients surveyed that have experienced a reduction in symptoms is between 0.1797 and 0.5346.

2)

We are certain that 95% of patients will be between 0.1797 and 0.5346.

3)

We cannot determine the proper interpretation of this interval.

4)

We are 95% confident that the proportion of all patients on the drug regimen that have experienced a reduction in symptoms is between 0.1797 and 0.5346.

5)

We are 95% confident that the proportion of patients who should be on this drug is between 0.1797 and 0.5346.

Suppose you want to determine the average height of college basketball players in NCAA Division I. In a random sample of 13 players, the sample average is 71.74 inches with a standard deviation of 5.0141 inches. What is the 90% confidence interval for the average height of all NCAA D-I players?

Question 6 options:

1)

( -69.261 , 74.219 )

2)

( 70.349 , 73.131 )

3)

( 69.958 , 73.522 )

4)

( 69.261 , 74.219 )

5)

( 69.277 , 74.203 )
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Answer #1

solution- 243 Margin of eroor = Talo p (-6) = 2.58 x 1 - 10:1860] 0.1260 4 we are 95% confident that proportion is between 0.

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