Question

A pharmaceutical company is testing a new drug to increase memorization ability. It takes a sample of individuals and splits them randomly into two groups: group 1 takes the drug, group 2 takes a placebo. After the drug regimen is completed, all members of the study are given a test for memorization ability with higher scores representing a better ability to memorize. Those 29 participants on the drug had an average test score of 27.92 (SD = 3.215) while those 20 participants not on the drug (taking the placebo) had an average score of 24.87 (SD = 4.148). You use this information to perform a test for two independent samples with hypotheses Null Hypothesis: μ₁ ≤ μ₂, Alternative Hypothesis: μ₁ > μ₂. What is the test statistic and p-value? Assume the population standard deviations are equal.

Question 14 options:

	1) Test Statistic: 2.898, P-Value: 0.0028
	2) Test Statistic: 2.898, P-Value: 0.9972
	3) Test Statistic: 2.898, P-Value: 0.0056
	4) Test Statistic: -2.898, P-Value: 0.0028
	5) Test Statistic: -2.898, P-Value: 0.9972

Answer 1

The statistic software output for this problem is:

Two sample T summary hypothesis test: Vi : Mean of Population 1 P2 : Mean of Population 2 V1 - H2 : Difference between two means Ho: M1 - 2 = 0 HA: V1 - H2> 0 (with pooled variances) Hypothesis test results: Difference Sample Diff. Std. Err. DF T-Stat P-value - 2 3.05 1.0525446 47 2.8977393 0.0028

Test Statistic: 2.898, P-Value: 0.0028

Option 1)