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CAN YOU SHOW ALL STEPS PLEASE
Ch 3, Interest and Equivalence So You Wanna be an Engineer/CM 3-3 You put $1000 into a savings account at EOYO and EOY1. How
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Answer #1
Annual rate of interest 7.20%
Interest is paid 3 time per year it means interest rate per period = 2.40% (7.20%/3)
Number of period for amount deposited EOY0 = 9 periods (3*3)
Number of period for amount deposited EOY1 = 6 periods (3*2)
Future value of money deposited EOY0 = Deposit amount * (1+rate per period)^(number of periods)
Future value of money deposited EOY0 = 1000*(1+0.024)^9
Future value of money deposited EOY0 = 1237.94
Future value of money deposited EOY1 = Deposit amount * (1+rate per period)^(number of periods)
Future value of money deposited EOY1 = 1000*(1+0.024)^6
Future value of money deposited EOY1 = 1152.92
Hence, total amount in deposit account at end of 3 years 2390.86 (1237.94+1152.92)
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