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Question 10 (1 point) Saved There is a group of four independent projects: W, X, Y, and Z. Assuming there are not funding or

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It is a permutation question.
Number of alternatives of among 4 projects can be calculated as factorial 4.
Factorial 4= 4*3*2*1
Factorial 4= 24
But this will include repetition of projects too,
So maximum number of alternatives should be - factorial 4/2
So maximum number of alternatives should be - 24/2
So maximum number of alternatives should be - 12
So answer is 12.
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