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Question 2. Consider a random variable X~x20 - Answer the following. i) ii) What are E(X) and Var(X)? What value is the value

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ANSWER:

given that:

Consider a random variable X \sim X220

let US consider,

A random variable X \sim X220

let,

X fallow chi - square distribution with 20 degree of freedom ( df ) .

(i) What are E (X) $ Var ( X )

we know that,

if X follows chi- square with n degree of freedom , then

It's mean is given as n $ variable as 2n.

E [ X ] = 20

Var ( X ) = 40

( ii ) what value is the value X20,0.12 that catisties P ( X220  > X20,0.12  ) = 0.1

For 20 df $ e

10 % ( 0.1) level of significance.

we have from the chi-square table.

\Rightarrow P(X_2>28.4)=0.1

so,

our required value is 28.4

(iii) use the central limit theorem to find the value  \Rightarrow P(\bar{X}>x)=0.1

we have ,

E[X_{i}]=20

Var [X_{i}]=40

so ,

E [X_{i}]=20

Var[\bar{X}]=\frac{Var(X)}{N}=\frac{40}{40}=1

Var[\bar{X}]=1

Now by using

Central limit theorem:

Z=\frac{\bar{X}-E[X]}{\sqrt{Var(\bar{X})}}\sim N(0,1)\, \, as\, \, \, n\rightarrow \infty

Z=\frac{\bar{X}-20}{1}

We know that,

p[Z> 1.28]=0.1

\therefore X^{*}=1.28

( i V ) wthat would you expect would happen to the value x* as the sample size n increales ? why

Due to,

Central limit theorem :

There won't be signifficant change in the value of Z as n is increases

Hence ,

The value of X* = 1.28

will remain same as n increaser.

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