ANSWER:
given that:
Consider a random variable X
X220
let US consider,
A random variable X
X220
let,
X fallow chi - square distribution with 20 degree of freedom ( df ) .
(i) What are E (X) $ Var ( X )
we know that,
if X follows chi- square with n degree of freedom , then
It's mean is given as n $ variable as 2n.
E [ X ] = 20
Var ( X ) = 40
( ii ) what value is the value X20,0.12 that catisties P ( X220 > X20,0.12 ) = 0.1
For 20 df $ e
10 % ( 0.1) level of significance.
we have from the chi-square table.
so,
our required value is 28.4
(iii) use the central limit theorem to find the
value
we have ,
so ,
Now by using
Central limit theorem:
We know that,
( i V ) wthat would you expect would happen to the value x* as the sample size n increales ? why
Due to,
Central limit theorem :
There won't be signifficant change in the value of Z as n is increases
Hence ,
The value of X* = 1.28
will remain same as n increaser.
Question 2. Consider a random variable X~x20 - Answer the following. i) ii) What are E(X)...
Let X1, ..., X20 be independent Poisson random variables with mean one. 1 2 (a) Use the Markov inequality to obtain a bound on P (X1 + X2 + · · · + X20 > 15). (b) Use the central limit theorem to approximate the above probability.
Suppose that X. X. .... Xso denote a random sample of measurements on the proportion of impurities in iron ore samples. Let each variable X, have a probability density function given by fx/X) = 3x2 0<x< 1. The ore is to be rejected by the potential buyer if X1 + X2+...+X40 exceeds 2.8. Let X = X1 + X2 + ....+X40. Find Var). Answer:
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suppose x is the mean of a random sample of size n=36 from the chi-squared distribution with 18 degrees of freedom. use the central limit theorem to approximate the probability P(16 < x < 20) ?
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by
central limit theorem
12. Suppose that X1, X2, ..., X 40 denote a random sample of measurements on the proportion of impurities in iron ore samples. Let each variable X have a probability density function given by 132 0<x<1 o elsewhere The ore is to be rejected by the potential buyer if sample of size 40 X, exceeds 2.8. Estimate P ., X. > 2.8) for the
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R commands
2) Illustrating the central limit theorem. X, X, X, a sequence of independent random variables with the same distribution as X. Define the sample mean X by X = A + A 2 be a random variable having the exponential distribution with A -2. Denote by -..- The central limit theorem applied to this particular case implices that the probability distribution of converges to the standard normal distribution for certain values of u and o (a) For what...
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