Question

Calculate the derivatives of the following functions: 1) y = 3x2 GC - 36236) dy 2) y = 5/x2 3) y = 3x2 + 4x + 7 Assignment 3 - Finding a Minimum and Maximum of a Function Find the minimum or maximum of the following functions: 1) y = 5x² - 4x-1 1-sace - 400 2) y = -3x2 + 2x + 8 Assignment 4 - Graphs of Linear and Quadratic Functions Please draw graphs for the following linear functions: y = 2 x - 3 y = 2 x + 3 y = -2x + 3 y = -2x - 3 2x + 3y = 6 2x - 3y = 6 - 2x + 3y = 6 - 2x - 3y = 6

can someone please do this for me

Answer 1

1 y = 3x2 d. an- nuh ax dy = 54-2222-1 au = -1073 3) y = 3x² + 4x +7 y = 6274 du Assignment 3 1) y = 58²_4u-1 dy z lore-4 are put do to, dze - louay tor-4²0 xz 4 = 0.4 1070 an : x=0.4 is point of minimum. y = - 322 + 2x+8 dze put dy 62+2=0 =0, 2= 62 = > x= 1 dy = - 6 CO dra

Thus, *pure of macinecom Thus, wat is point of maximum. Assignmenty y = - 2273 y = 2x-3 y =ant 3 ay y = -28-3 10,32 40-27-3 y= 22-3 102, -2% +3 y = y=2x+3 y = 2n-3 x=0, y=-3 y=0, x= 3 y = - 2x +3 2=0, y=3 y=0, x=312 y = -22-3 y = aut3 y =0, x=-2 / x=0, y=3 y=0, x=-3

2х + 3 = 6 Х. Е.О, 9 : 2 5-о, х = 3 2х - 32 = 6 х = 0, 2= - 2 что, x = 3 - 2x + 2 = 6 х: О, Я = 2 2 = 0, х = -3 - 2х - 34 = 6 х= 0, 2 = -2 ЧЕо, х = -3 6 = 2x+39 - 4 -2х-+ 3 2х-39 = 6 (-3,0) to,-2) -21-39 Е .