. Find the first derivatives (dy/dx) for each of the following functions. Do not need to simplify. (3 points each)
A. y = (2x^5 + 3x^3)^2
B. y = (8x^3-56x^2+3x)/(x+12)
C. y= (6x2 + 3x) (x – 4x3)
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. Find the first derivatives (dy/dx) for each of the following functions. Do not need to...
Below are eight functions. Find the first derivative of each. Space is provided. Use good dark ink if you are returning this by a scanned version. All of the derivatives can be found by using combinations of the constant rule, power function rule and sum-difference rule. Do not use the product rule. It is not needed. The degree of difficulty (more or less) increases from (a-h). Be sure to show intermediate work. Check the scoring rubric to see how the points are awarded. For example, the first...
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5. (5 points each) Compute the following derivatives. Do not simplify. dy (a) Let y = cos (3.1). Find der (b) Let f(t) = de-+ +5e". Find f(*)(t). (c) Let g(t) = ln(2) sec(1). Find d'(I). df (d) Let f(t) = " + x + ex. Find dar ind
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Find the stationary values of the following functions, and determine whes they give maxima, minima, or points of inflection (a) y 0.5x3 -3x2 +6x + 10 3. (c) y x-4x3 + 16x (d) y-x +1/x (e) y 3-3x -1 ( y x- 10x3 +6x2 +5
3x+2 f(x) =( :) (x-> +1) Your problem: using the rules of differentiation, find the derivatives of the collowing: f)-(3442) fool(3x+2) (-5x + x + 1) - 2 1 =(-15x 10x" + (-2x = 2) =>15x410x5 - 2x = = 3x -3x- 27 (X)(3+0)-(3x+2)(1) x² g'=(x) =F12x15x4_2 = -5x6 xb * please check my work, if wrong, please write out correct solation! Chain Rule: When functions are composed, to take the derivative involves both the outside function and the inside...
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can someone please do this for me Calculate the derivatives of the following functions: 1) y = 3x2 GC - 36236) dy 2) y = 5/x2 3) y = 3x2 + 4x + 7 Assignment 3 - Finding a Minimum and Maximum of a Function Find the minimum or maximum of the following functions: 1) y = 5x² - 4x-1 1-sace - 400 2) y = -3x2 + 2x + 8 Assignment 4 - Graphs of Linear and Quadratic Functions...