Question

How to solve these problems?

18. A tube feeding is scheduled QID of Sustacal full strength at 50 ml/hr. The feeding will run If the nurse wants to put enough feeding for 6 hours, how feeding bag? many ml of feeding would you put in the Answer If the cans hold 240 ml, how many cans will you use? Answer can(s) If the Dr. changes the order to 34 strength at 50 ml/hr, how much water and how much Sustacal will be used to run the feeding for 6 hours via pump? Answer mL of water Answer mL of feeding How many cans will be needed for the Yo strength to run 6 hours? Answer can 19. 1 L of Ds1/2NS is ordered to be given in 12 hours. Drop factor is 20 gtts/ml. How many gtts/min.? Answer

Answer 1

Answer 1.

50 ml/ hr sustacal in 1 hour.

That means ,for 6 hours = 6hours × 50ml = 300 ml

So, 300 ml feed is needed to administer in 6 hours .

Answer 2.

For administering sustacal for 6 hours ,

One can hold 240 ml ,

To hold 300 ml 2 cans will be needed.

Answer

For 6 hours= 6× 50 ml/ hr= 300 ml total solution is needed

Calculate

D×Q= 3/4× 300 ml

= 225 ml feed will be needed

And 300- 225 = 75 ml water is needed.

Answer : 225 ml of feeding

Answer : 75 ml of water.

Answer

From above solution we can conclude that one can holds 240 ml ,and we have to administer 225 ml of feed so only 1 can is needed, 75 ml water can be added later.

Answer is 1 can

Answer 9 .

gtts/min= ml /hr× drop factor.

1litre D5 1= 1000 ml

And in minutes,

12 hr × 60 = 720 min.

gtts/min= ml/ hr× drop factor.

= 1000(ml) ÷720(min) × 20 (drop factor)

gtts/ min = 27.7

~ 27 Answer