Homework Answers
Answer :
1. The expected f2 genotypes are 9 unique genotypes.
Expected genotypes and phenotypes arrays from two unlinked genes, considered jointly are the product of the supperate genotype and phenotypes arrays. For example when A gene and B gene considered jointly, there will be a 3 × 3 or 9 genotypes.
2.f2 phenotypes are 9 height classes.
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8. If two Fl progeny from the zwoof cross deseribed above mate, what are the expected...
3 Chapter 7-Multifactorial Traits Height in a particular Martian biped rodent, the zwoof, is controlled by...
3 Chapter 7-Multifactorial Traits Height in a particular Martian biped rodent, the zwoof, is controlled by two different loci on two differernt chromosomes. The trait obeys a "simple additive loci model" The recessive alleles a and b each contribute 2 inches of height. The dominant alleles . A and B each contribute 6 inches of height .Therefore, a zwoof that is homozgous tall (AABB) at each locus is 24 inches tall. A zwoof that is homozygous dwarf (aabb) is 8...
4. You cross individuals with the following Genotypes, AaBbDdEeFFGg & AaBbDDEeFfGg. Predict the proportion of offspring...
4. You cross individuals with the following Genotypes, AaBbDdEeFFGg & AaBbDDEeFfGg. Predict the proportion of offspring that would show the following Phenotype or Genotype? A) all Dominant Phenotypes, B) the Genotype: AabbDdEeFfgg, C) the Genotype: AABbDdEeFfgg, D) the Genotype: aaBbddEeffGg, & E) all Recessive Phenotypes. 5. You cross individuals with the following Genotypes, AaBbDdEeFFgg x AabbDDEeFfGg. If you produce 1000 offspring in this cross, predict the number of offspring that would have the following Phenotype or Genotype? A) all Dominant...
The results for the F2 progeny are shown for a F1 cross using the two X-linked...
The results for the F2 progeny are shown for a F1 cross using
the two X-linked markers:
w+ and m+.
As shown in the figure, the F1 cross is between the following
two parents:
- a phenotypically wild-type (red eye, full wing), heterozygous
female: w+m+/wm
- a double mutant male (white eye, miniature wing):
wm/Y
Answer the following questions:
1) In the F1 cross, can you infer the genotype for the phenotype
in the female? Why or why not?
2)...
(More Genetics Problems and Difficult Genetics Problems). MORE GENETICS PROBLEMS 1. When tall plants mate with...
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1. What would be the phenotype for each of the following birds, including their gender? Color...
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You are working with an ornamental fish that shows two color phenotypes, red or blue. The...
You are working with an ornamental fish that shows two color phenotypes, red or blue. The color is controlled by a single gene. These fish are hermaphrodites-meaning they can either (1) self-fertilize or (2) mate with another fish. You have three fish: fish 1, fish 2, and fish 3. While working further with this fish, you discover one other mutation (in a different gene) that leads to the recessive phenotype of long dorsal fins. Further research establishes that the genes...
Bio215 Problem Questions Hassanaton MULTIPLE CHOICE 1) Pea plants were particularly well suited for use in...
Bio215 Problem Questions Hassanaton MULTIPLE CHOICE 1) Pea plants were particularly well suited for use in Mendel's breeding experiments for all of the following reasons exep that ) peas show easily observed variations in a number of characters, such as pea shape and flower color. B) it is possible to completely control matings between different per plants. C) it is possible to obtain large numbers of progeny from any given cross. D) peas have an unusually long generation time. E)...
please solve qs12-23 and include explanations thanks A wild-type trihybrid soybean plant Phenotype Number is crossed...
please solve qs12-23 and include explanations thanks
A wild-type trihybrid soybean plant Phenotype Number is crossed to a pure-breeding Pale 648 soybean plant with the recessive Pale, oval phenotypes pale leaf (), oval seed Pale, short 10 (r), and short height (t). The results Pale, oval, short 102 of the three-point test cross are Oval shown in the table. Traits not listed Oval, short 618 are wild-type. Short 84 Wild type 98 1. True False The phenotypes 1630 listed in...
1. People wit h the sex-linked genetic disease, hemophilia, suffer from excessive bleeding because their blood...
1. People wit h the sex-linked genetic disease, hemophilia, suffer from excessive bleeding because their blood will not clot. Tom, Mary, and their 4 daughters do not exhibit symptoms of hemophilia. However, their son exhibits symptoms of hemophilia because: A) Tom is heterozygous B) Tom is homozygous C Mary is homozygous D) Mary is heterozygous E All of the above are equally likely What is the risk of having a child affected by disease with an autosomal recessive inheritance both...
For questions 5 and 6: Tall (T) is dominant to short (t) 5. Ifa homozygous tall...
For questions 5 and 6: Tall (T) is dominant to short (t) 5. Ifa homozygous tall plant is crossed with a short plant, what percentage of the offspring will be tall? , The two parents used in this cross are called as breeding parents. 6. Iftwo heterozygous tall plants from the above are crossed, what percentage of the offspring will be short? For questions 7, 8 and 9: Purple (R) is dominant to white (r) If two white flowered plants...
3 Chapter 7-Multifactorial Traits Height in a particular Martian biped rodent, the zwoof, is controlled by two different loci on two differernt chromosomes. The trait obeys a "simple additive loci model" The recessive alleles a and b each contribute 2 inches of height. The dominant alleles . A and B each contribute 6 inches of height .Therefore, a zwoof that is homozgous tall (AABB) at each locus is 24 inches tall. A zwoof that is homozygous dwarf (aabb) is 8...
The results for the F2 progeny are shown for a F1 cross using
the two X-linked markers:
w+ and m+.
As shown in the figure, the F1 cross is between the following
two parents:
- a phenotypically wild-type (red eye, full wing), heterozygous
female: w+m+/wm
- a double mutant male (white eye, miniature wing):
wm/Y
Answer the following questions:
1) In the F1 cross, can you infer the genotype for the phenotype
in the female? Why or why not?
2)...
(More Genetics Problems and Difficult Genetics Problems). MORE GENETICS PROBLEMS 1. When tall plants mate with dwarf plants, only tall plants occur in the offspring. Assign symbols and show the phenotypes and genotypes in the parental (P) and first filial generations for a cross between tall plants and dwarf plants that produces only tall plants. 2. Show the expected outcome when the F1 plants in problem #1 are crossed. Be sure to give both phenotype and genotype ratios for these...
You are working with an ornamental fish that shows two color phenotypes, red or blue. The color is controlled by a single gene. These fish are hermaphrodites-meaning they can either (1) self-fertilize or (2) mate with another fish. You have three fish: fish 1, fish 2, and fish 3. While working further with this fish, you discover one other mutation (in a different gene) that leads to the recessive phenotype of long dorsal fins. Further research establishes that the genes...
Bio215 Problem Questions Hassanaton MULTIPLE CHOICE 1) Pea plants were particularly well suited for use in Mendel's breeding experiments for all of the following reasons exep that ) peas show easily observed variations in a number of characters, such as pea shape and flower color. B) it is possible to completely control matings between different per plants. C) it is possible to obtain large numbers of progeny from any given cross. D) peas have an unusually long generation time. E)...
please solve qs12-23 and include explanations thanks
A wild-type trihybrid soybean plant Phenotype Number is crossed to a pure-breeding Pale 648 soybean plant with the recessive Pale, oval phenotypes pale leaf (), oval seed Pale, short 10 (r), and short height (t). The results Pale, oval, short 102 of the three-point test cross are Oval shown in the table. Traits not listed Oval, short 618 are wild-type. Short 84 Wild type 98 1. True False The phenotypes 1630 listed in...
1. People wit h the sex-linked genetic disease, hemophilia, suffer from excessive bleeding because their blood will not clot. Tom, Mary, and their 4 daughters do not exhibit symptoms of hemophilia. However, their son exhibits symptoms of hemophilia because: A) Tom is heterozygous B) Tom is homozygous C Mary is homozygous D) Mary is heterozygous E All of the above are equally likely What is the risk of having a child affected by disease with an autosomal recessive inheritance both...
For questions 5 and 6: Tall (T) is dominant to short (t) 5. Ifa homozygous tall plant is crossed with a short plant, what percentage of the offspring will be tall? , The two parents used in this cross are called as breeding parents. 6. Iftwo heterozygous tall plants from the above are crossed, what percentage of the offspring will be short? For questions 7, 8 and 9: Purple (R) is dominant to white (r) If two white flowered plants...
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