Find the PW of both methods (repeat the cash flows for A twice for LCM = 12)
PW(A) = -8000 – 8000(P/F, 10%, 6) – 700(P/A, 10%, 12) + 900(P/F, 10%, 6) + 900(P/F, 10%, 12)
= -8000 – 8000*0.56447 - 700*6.8137 + 900*0.56447 + 900*0.31863
= - $16490.56
PW(B) = -10000 – 800(P/A, 10%, 12) + 700(P/F, 10%, 12)
= -10000 – 800*6.8137 + 700*0.31863
= - $15227.91
Since PW(B) > PW(A) select alternative B
A company needs a new mechanical device. Compute the present worth for these mutually exclusive alternatives....
The Larkspur Furniture Company needs a new grinder. Compute the present worth for these mutu- ally exclusive alternatives and identify which you would recommend given i = 6% per year. Larkspur uses a 10-year planning horizon. Alternative A B Initial cost Annual costs Salvage value Life $4500 $300 $500 5 years $5500 $400 $0 10 years
i dont want excel answer 5- The Larkspur Furniture Company needs a new grinder. 37 Compute the present worth for these mutually exclusive alternatives and identify which you would recommend given i = 6% per year. Larkspur uses a 10-year planning horizon. Alternative B A Initial cost $4500 $5500 Annual costs $300 $400 Salvage value $500 $0 Life 5 years 10 years
57 The Larkspur grinder. Compute ally exclusive alta would recommend pin sour Furniture Company needs a new Compute the present worth for these mutu- alusive alternatives and identify which you Sammend given i = 6% per year. Larkspur uses a 10-year planning horizon. Alternative A $5500 $400 Initial cost Annual costs Salvage value Life $4500 $300 $500 5 years 10 years Cowtributed by Gillian Nicholls, Southeast Missouri State University
Question 4. (20 points): The Big Discount Furniture Store (BDFS) needs a new generator. Compute the present worth for these mutually exclusive alternative and identify which you would recommend giving the interest ratei - 5,5% per year. BDFS use a 10-year planning horizon. Alternative Initial cost Salvage value Life $4500 $500 5 years $5500 $0 10 years
QUESTION 6 Data for two mutually exclusive alternatives are given below. Alternatives B $4,000 $800 А Initial Cost $5,000 Annual Benefits (beginning at end of $1,500 year 1) Annual Costs (beginning at end of year $500 1) Salvage Value $500 Useful Life (years) 5 $200 $0 10 Compute the net present worth for each alternative and choose the better alternative. MARR = 8%
5-68 Consider A-E, five mutually exclusive alternatives: A B C D E Initial cost $800 $800 $800 $800 $800 Uniform annual benefits For first 6 years 125 150 100 125 150 For last 6 years 40 80 120 50 50 The interest rate is 8%. If all the alternatives have a 12-year useful life and no salvage value, which alternative should be selected?
ANSWER THE FOLLOWING QUESTIONS:- Three mutually exclusive design alternatives are being considered. The estimated cash flows for each alternative are given. The interest rate is 20% per year. At the conclusion of the useful life, the investment will be sold A C Investment cost $28,000 $55,000 $13,000 $28,000 $8,000 $40,000 Annual expenses Annual revenues $15,000 $23,000 $6,000 10 years $22,000 $32,000 13 $10,000 Salvage value Useful life 10 years 10 years A decision-maker can select one of these alternatives or...
Problem (2): Consider the following three mutually exclusive alternatives. MARR is 10%. Alternative 1 10,000 Alternative 2 14,500 Alternative 3 20,000 $3,000 increasing by 500 each year thereafter negligible $5,000 Initial investment Annual yielded returns Salvage Value Service life $5,000 $5,000 negligible 6 a) Compute the payback (PB) period and discounted PB period of each alternative. Based on the PB period, which alternative do you recommend? b) Using Annual-worth analysis, which alternative do you recommend?
4. (10 points) A firm is considering three mutually exclusive alternatives as part of a production improvement program. The alternatives are: Initial Cost $20,000 $30,000 $50,000 Uniform Annual Benefit $4,000 $5,000 $6,500 Useful Life Salvage Value $2,000 $9,000 The MARR is 10%. Which alternative do you recommend? Be sure to use the proper technique when comparing alternatives with different useful lives.
Assume a mutually exclusive scenario. Compare three alternatives on the basis of their capitalized cost (CC) at i=10% per year, which is the best alternative in this scenario? • Alternative 1, AW = $87,500 and n = (forever) • Alternative 2, PW = -$895,000 and n = (forever) • Alternative 3, First cost (FC) of $900,000, annual operating savings of 3,000 per year, salvage = $200,000, and n = (forever) Alternative 2 Alternative 3 None of them Alternative 1 QUESTION...