Question

7. (Points: 10): The Mechanical Engineering department has a student team that is designing a formula car for national competition. The time required for the team to assemble the first car is 150 hours. Their improvement (or learning rate) is 0.75, which means that as output is doubled, their time to assemble a car is reduced by 25%. Use this information to determine a) The time it will take the team to assemble the 10th car. b) The total time required to assemble the first 10 cars. c) The estimated cumulative average assembly time for the first 10 cars.

Please answer parts a through c by hand, no spreadsheet. & please post formulas used. Thank you!

Answer 1

If time required for on the car is Tn. then time required for (h+1)th car is Trai - Ta - Tu x 25 this is because time reduced by 25% when outi doubled. in Tere Te - 25 Th (75) no. of cars Time take (murs) ne and time taken tor T = 150 first can 150 hours T2 = 112.5 = 84.375 Th = 63-28125 = 47 4609 375 - 35.595703125 = 26.696 777 3437 = 20 02 258 30078 - 15 016 9372558 1. 1 26270 2 9 418 I is time for making I st can then, T = T (175) " ドドドドドドドド *

6 Time to assemble loth car is boy 1.26 27 29418 hows Total time required to assemble first 10 car is { Ti (iz 1 to 10) = T. & T. (175) + Te (757 – – &T, (75) 2 T. [1 - (-7510 ] tormula o f G.P. series [ - 75] (1-x) 2 566.211891174 an first torm 7 = common ratio T. 2150 cummulative are rage assembly time for first 10 cars - ETi z 560.2 1189 174 hours. 25 6.6 211 891 74 7