Free energy change of a chemical process is given by , Go = -2.303RTlogKc
Given that free enrgy change of conversion from G 1p to G 6p = - 7.1 kj/mol.
Given that free enrgy change of conversion from G 6p to G 1p = - 2 kj/mol.
G 1p G 6p
so free energy change for the reversible process above = -7.1 - (-2.0) kj/mo
= -5.1 kj/mol
For the above process , Kc = [G 6p] / [G1p]
Temperature = 273 + 37oC
= 310k
But Go = -2.303RTlogKc
for the above process ,given that , Go = - 5.1 kj/mol. = -5100 j/mol
so logKc = 5100 j/ 2.303RT
= 5100 j / 2.303 x 8.3145 j/k.mol x 310 k
= 0.85917
Kc = 100.85917
=7.23
or concentration ratio ASKED , [G 6p] / [G1p] = 7.2
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