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3. Limits. The limits below do not exist. For each limit find two approach paths giving different limits Calculate the limits

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Answer #1

Plus Dele Question- Answer Sink C1-c0y put yeal ong Las Path Path 1 Binx C1-Cosx) m Form 0 KO 2 using LHobials ele- K-a. inPlus Date cosintx - COS2X+(o 3 Cos2K 4gain fosm ayain ue LHabital So we +ih2x 2+Sinn) 212x2 1m NoW Pathng mits 2 NOw pathe alI-Coy nly 4 2 ) 2 txlivA (-COsy Form fo ing tbsbals Yle L iny 22 4 So we can geer Patla lale gat taa diffeont imits thAp doTARANG P. No. Dake Plus Ansher X ,0)c0s2+ InK1y2) te e can as 4yO0) (at nyIne Lim neT + Here we can YPman modulus sign PathftTARANG P No. Date Form Cos using LMeshials Yule 3 x Lim -sin a 2x-O Itx2 ajain Form(0 3K Itx2 again So L, Hoshital rale I+2.TARANG , No Plus Det Path alon tar path DT t eyeslnlige Li Mespitas v4le -O again Fam +ay thabk nle ajain timPius Date 22 2 2 +2 L 0)2 So again in this limit als a 1mt dit ferint valne a long NSnent paths exists So, limit dees no ns

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