Question

A study of reading comprehension in children compared three methods of instruction. The three methods of instruction are called Basal, DRTA, and Strategies. As is common in such studies, several pretest variables were measured before any instruction was given. One purpose of the pretest was to see if the three groups of children were similar in their comprehension skills. The READING data set described in the Data Appendix gives two pretest measures that were used in this study. Use one-way ANOVA to analyze these data and write a summary of your results.

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subject group   pre1    pre2    post1   post2   post3
1       B       4       3       5       4       41
2       B       6       5       9       5       41
3       B       9       4       5       3       43
4       B       12      6       8       5       46
5       B       16      5       10      9       46
6       B       15      13      9       8       45
7       B       14      8       12      5       45
8       B       12      7       5       5       32
9       B       12      3       8       7       33
10      B       8       8       7       7       39
11      B       13      7       12      4       42
12      B       9       2       4       4       45
13      B       12      5       4       6       39
14      B       12      2       8       8       44
15      B       12      2       6       4       36
16      B       10      10      9       10      49
17      B       8       5       3       3       40
18      B       12      5       5       5       35
19      B       11      3       4       5       36
20      B       8       4       2       3       40
21      B       7       3       5       4       54
22      B       9       6       7       8       32
23      D       7       2       7       6       31
24      D       7       6       5       6       40
25      D       12      4       13      3       48
26      D       10      1       5       7       30
27      D       16      8       14      7       42
28      D       15      7       14      6       48
29      D       9       6       10      9       49
30      D       8       7       13      5       53
31      D       13      7       12      7       48
32      D       12      8       11      6       43
33      D       7       6       8       5       55
34      D       6       2       7       0       55
35      D       8       4       10      6       57
36      D       9       6       8       6       53
37      D       9       4       8       7       37
38      D       8       4       10      11      50
39      D       9       5       12      6       54
40      D       13      6       10      6       41
41      D       10      2       11      6       49
42      D       8       6       7       8       47
43      D       8       5       8       8       49
44      D       10      6       12      6       49
45      S       11      7       11      12      53
46      S       7       6       4       8       47
47      S       4       6       4       10      41
48      S       7       2       4       4       49
49      S       7       6       3       9       43
50      S       6       5       8       5       45
51      S       11      5       12      8       50
52      S       14      6       14      12      48
53      S       13      6       12      11      49
54      S       9       5       7       11      42
55      S       12      3       5       10      38
56      S       13      9       9       9       42
57      S       4       6       1       10      34
58      S       13      8       13      1       48
59      S       6       4       7       9       51
60      S       12      3       5       13      33
61      S       6       6       7       9       44
62      S       11      4       11      7       48
63      S       14      4       15      7       49
64      S       8       2       9       5       33
65      S       5       3       6       8       45
66      S       8       3       4       6       42

Answer 1

Answer For the given scenario, the null and alternative hypotheses are stated as below: Null hypothesis: Ho : 1 2 = 43 = p4 = H5 Date: --26/6/2019 Alternative hypothesis: H1 Treatmentmeansarenotallthesame

Using the Excel follow the steps mentioned below 1Type or import the data in three columns. One column contains the test pre-1 another contains pre-1, post -1, post -2 and post-3. 2.Click on the Data tab. Select Data Analysis 3.Click OK Anova: Single Factor. 4.Select the columns in the input range and enter alpha as 0.05. 5.Click OK Follow the above instructions to get the ANOVA output as shown below: Anova: Single Factor SUMMARY Groups Count Sum Average Variance Pre 1 66 646 9.78788 9.12354 337 Pre 2 66 5.10606 4.89627 Post 1 66 533 8.07576 11.5172 Post 2 66 443 6.71212 6.94662 2905 Post 3 66 44.0152 441382 ANOVA F crit df P-value Source of Variation Between Groups Within Groups SS MS F 71493.2 4 17873.3 1166.33 2.628E-191 2.39943 15.3244 4980.42 325

Total 76473.6 329 From the above output, the decision rule is to reject Ho, if F 2.399 for a = 0.05 level of significance. Therefore, Feal 2.399 at a 0.05, so conclude that the results are significant. There is significant difference between the children regarding their comprehension skills.