Question

Please show all work and where you get each value from. Don't assume i know where you get a value from. Thank you

3. Calculate total head loss in a new galvanized iron pipe with the length of 1000 m and diameter of 12", if the total flow rate is: a) 0.2 cfs, b) 0.9 cfs. If the max HL is 5 ft per 1000 ft, evaluate a and b scenarios. Assume the temperature 20°C. How do you evaluate Velocity in this system? (40 points)

Answer 1

Ist Part Given - 32 80. 84ft L = O OO m D 12 inah 2/gee -6 y (at 20'c) 1.007 X1D - S 1-88 X10 ft/3ec -4 = 3 6X 10 Galvanized iron 2 3.3x10-4 < E<1.5 x 10 = 0.0006 ft Relative Roughaess 0.0006 E O.0006 1 Q = O. 2 VD Re D A 4Q Y 4X 6.2 Re = - 1354 S 4000 AXIX 1.8 8 X 1O . Turbulent flow

Values of (VD) for water at 60 F (diameter in inches, velocity in ft./sec.) 2 0.4 0.6 400 600 1000 2000 10,000 0.1 0.2 4 6 10 20 40 60 100 200 4000 0.10 Laminar flow,f- 0.09 0.08 0.05 0,07 0.06 0.03 0.05 0.02 -늬부 0.04 0.01 II 0.006 0.03 0.004 0.025 0.002 0.020 0.001 0.0006 0.0004 t. 0.015 mm 0.003-03 0.001-d01 0.0006-0.003 85 0.0005 Riveted steel Cancrete Wood stave 0.9-9 0.0002 03-3 0.18-09 Smooth pipes Cavanized iron 0.15 Asphalted cast iran Steel or wrought iron Drawn Tubing 0.0004 0.00015 0.00000 0.12 0045 00015 0.00005 0.010 0.009 0.008 103 2(10 4 6 8 10 2(10 4 6 8 10 2(10) 4 6 8 10 2(10 4 6 8 10 2(10) 4 6 8 10 1.3545*10^4J Revndds number, Re = VD Fig. (a) Friction factor, f=LY Relative roughness,

Oing Mod Chert O.0006 O 0006 1 4 1. 3545 X1o &Re- 1 35 45 Corresponding value f uing chart [ig @] f = 0. 03 v2 H X () 2 0.2 32 80. 84 O 03X EA] (1)2 2x 32.2 : 0. 0991 ft O. 0991x 12 HL 1.18g inch ul4

Values of (VD) for water at 60 F (diameter in inches, velocity in ft./sec.) 2 0.4 0.6 400 600 1000 2000 10,000 0.1 0.2 4 6 10 20 40 60 100 200 4000 0.10 Laminar flow,f- 0.09 0.08 0.05 0,07 0.06 0.03 0.05 0.02 -늬부 0.04 0.01 II 0.006 0.03 0.004 0.025 0.002 0.023 0.020 0.001 0.0006 0.0004 t. 0.015 mm Riveted steel Cancrete Wood stave 0.003-a03 0001-0.01 0.0006-0.003 85 0.9-9 03-3 0.18 09 0.0002 Smooth pipes Cavanized iron 0.15 Asphalted cast iran Steel or wrought iron Drawn Tubing 00004 0.00015 0.000005 0.12 0045 00015 0.00005 0.010 0.009 0.008 103 2(10 4 d 8 10 6.0953 10 4 2(10 4 6 8 10 2(10) 4 6 8 10 2(10 4 6 8 10 2(10 4 6 8 10 VD Reynolds number, Re Fig. (b) Friction factor, f= Relative roughness,

b 4 Q 4x 0.9 Re = 60952.gs 4000 -S XIX I 88 X10 law Turbulent O.0006 O.O006 4 6.095 3X10 4Re 6095 3 Correapding uing Moedy Chertfg value f = O. O 23 レ2 HLf D 2 2 6.9 0.023 X 3 280.84 2x 32.2 こ.S386 ft 1.5386 X1 2 H = 1 8. 46 inch

2nd Part L = 100o a f = O.03 Since H f レ2 →5ニ0.03 2 X 32.2 1 ヤ Vニ 3.28ft/8ec Q VA A 2 VX 4 ftlsee 3.28 x 4 2.57 f = O.023 L ) 2 ng 2 レ2 X OoO S 0.02 3 2X 32.2 V = 3.74 ft/sec (1)2 2 94 .. a V×Aニ 3.74x 4- =