11. For nuclear reaction occurred in the Sun, 4H(z 1, A = 1) He(z 2, A...

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11. For nuclear reaction occurred in the Sun, 4H(z 1, A = 1) He(z 2, A = 4) +2e. calculate the energy released in kJ per mole

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Answer 1

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2e 4H (71 A He (2, A- 4) me 000055u mu=1.00子28 u mHeF 4.00150 (Am) defect in the follsing ieaction is, mas (mHe +2me 4mH Am = atoms 4 H So, -12 J energ ive 3.9592 xID So, for mole H energy amount onruld be, 23 6-023x 10 3.95 2 x 10 5-9616 5.9616 x 1

Ans: The amount of energy released is 5.9616 x 10⁸ kJ per mole of protons.

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11. For nuclear reaction occurred in the Sun, 4H(z 1, A = 1) He(z 2, A...

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11. For nuclear reaction occurred in the Sun, 4H(z 1, A = 1) He(z 2, A...

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