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(3E) Slinky Line. Consider R with the usual topology. Prove that R/N (see 3.12(e)) is Hausdorff but not first countable.

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Answer #1

Given x1 6= x2; choose xi 2 (ai; bi) possibly (a1; b1) \ (a2; b2) 6= ;:
We may assume that a2 < b1: If there is c 2 (a1; b1)\(a2; b2) then try (a1; c)
and (c; b2). Otherwise try (a1; b1) and (a2; b2):

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