Question

1. Inviscid incompressible fluid pass a cylinder having a radius of R as shown in the figure below. The fluid velocity along
0 0
Add a comment Improve this question Transcribed image text
Answer #1

(a)The expression for the fluid velocity along the stream line is V=V0(1-R2/x2)

here, V0 is the upstream velocity and R is the radius of the cylinder.

Calculate the pressure gradient along the stream line using the following equation

-\gammasin\theta - \partialp/\partials = \rhoV \partialv/\partials

\partialp/\partials = \gammasin\theta- \rhoV \partialv/\partials ..... (1)

here, \gamma is the specific weight of the liquid.

since the stream line is horizontal substitute 0 to  \theta in (1)

the acceleration term is given by the equation

V\partialv/\partials = V \partialv/\partialx

substitute V0(1-R2/x2) fpr V

V\partialv/\partials = V0(1-R2/x2) \partial V0(1-R2/x2)/ \partialx

= V0(1-R2/x2) [ V0(0-(-2R2/x3)]

= 2V02R2/ x3(1-R2/x2)

now substitute 2V02R2/ x3(1-R2/x2) for V\partialv/\partials and 0 for \theta in (1)

\partialp/\partials = -\gammasin 0 - \rho [2V02R2/ x3(1-R2/x2)]

the pressure gradient is [-2\rhoV02R2/ x3(1-R2/x2)]

(b) \partialp/\partials = \partialp/\partialx

replace the s by x because the 2 coordinates are identical along stream line.

\partialp/\partials = -2\rhoV02R2/ x3(1-R2/x2)

Integrate the above equation

P1\partialp = \int-2\rhoV02R2/ x3(1-R2/x2) x\partialx

p(x) -p1= -2\rhoV02R2\int[1/x3 - R2/x5] \partialx

p(x) -p1 = -2\rhoV02R2 [ -1/2x2 + R2/4x4]

p(x) -p1 = -2\rhoV02R2 - 1/2x2 - (-2\rhoV02R2 * R2/4x4)

p(x) = p1 + \rhoV02R2/x2 - \rhoV02R4/2 x4

(c) Calculate the P (x = -a) = P1 + \rhoV02R2/-a2 - \rhoV02R4/2 -a4

= P1 + \rhoV02 - \rhoV02/2

= P1 + \rhoV02/2

Add a comment
Know the answer?
Add Answer to:
1. Inviscid incompressible fluid pass a cylinder having a radius of R as shown in the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT