a)
Using the simple random sample applet, the 25 samples are,
Samples | 1 | 2 | 3 | 4 | Mean |
1 | 75 | 72 | 94 | 59 | 75 |
2 | 72 | 63 | 81 | 65 | 70.25 |
3 | 94 | 65 | 59 | 45 | 65.75 |
4 | 72 | 81 | 75 | 59 | 71.75 |
5 | 45 | 51 | 63 | 72 | 57.75 |
6 | 63 | 51 | 72 | 45 | 57.75 |
7 | 65 | 51 | 75 | 59 | 62.5 |
8 | 72 | 72 | 63 | 63 | 67.5 |
9 | 94 | 81 | 72 | 75 | 80.5 |
10 | 94 | 63 | 65 | 63 | 71.25 |
11 | 94 | 63 | 72 | 51 | 70 |
12 | 94 | 63 | 75 | 72 | 76 |
13 | 63 | 81 | 45 | 72 | 65.25 |
14 | 63 | 51 | 75 | 63 | 63 |
15 | 45 | 65 | 75 | 63 | 62 |
16 | 63 | 81 | 72 | 63 | 69.75 |
17 | 94 | 45 | 72 | 72 | 70.75 |
18 | 94 | 63 | 72 | 63 | 73 |
19 | 45 | 65 | 51 | 63 | 56 |
20 | 81 | 72 | 51 | 63 | 66.75 |
21 | 94 | 63 | 45 | 65 | 66.75 |
22 | 45 | 72 | 75 | 63 | 63.75 |
23 | 63 | 45 | 51 | 63 | 55.5 |
24 | 94 | 81 | 51 | 63 | 72.25 |
25 | 94 | 45 | 51 | 63 | 63.25 |
The histogram is obtained in following steps,
Step 1: Sort the data value,
Max | 80.5 |
Min | 55.5 |
Classes | 10 |
Class width | 2.5 |
Step 2: Count the data values withing the class
Bin | Frequency |
55.5 | 1 |
58 | 3 |
60.5 | 0 |
63 | 3 |
65.5 | 3 |
68 | 4 |
70.5 | 3 |
73 | 5 |
75.5 | 1 |
78 | 1 |
80.5 | 1 |
Step 3: Make a column plot.
b)
Using the histogram given, the mean and standard deviation values are obtained as follows,
mid pint, m | frequency, f | f*m | m-mean | (m-mean)^2 | f*(m-mean)^2 |
57 | 1 | 57 | -11.84 | 140.1856 | 140.1856 |
61 | 3 | 183 | -7.84 | 61.4656 | 184.3968 |
63 | 1 | 63 | -5.84 | 34.1056 | 34.1056 |
65 | 7 | 455 | -3.84 | 14.7456 | 103.2192 |
97 | 1 | 97 | 28.16 | 792.9856 | 792.9856 |
69 | 3 | 207 | 0.16 | 0.0256 | 0.0768 |
71 | 3 | 213 | 2.16 | 4.6656 | 13.9968 |
73 | 2 | 146 | 4.16 | 17.3056 | 34.6112 |
75 | 4 | 300 | 6.16 | 37.9456 | 151.7824 |
Sum | 25 | 1721 | 1455.36 |
The probability X>= 78 is obtained by calculating z score,
The probability for the z score is obtained using the standard normal distribution table,
Correct option: Hence the chances of obtaining is very unlikely
c)
Correct Answer: The mean for these four students is 78. Based on the results in part (a), we might conclude that the mean score for the four honors students was unusually high( that is, the mean is statistically significant)
Explanation:
Student | Score |
1 | 94 |
3 | 81 |
5 | 72 |
7 | 65 |
mean | 78 |
Since the p-value for the z statistic is 0.000 < 0.05 at 5% significant level hence statistically significant
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