Question

Below are 30 students' Research Methods Il grades from last acadenmic year. Consider this the "population" 75,85,95,96,98, 88, 85, 82,83,84, 80,77,79,76,72,95, 85,83,82,84.81,79,78,75, 80, 85, 96, 93,93, 88 Now, I chose four students at random from my Research Methods Il class this semester. Your job will be to tell me if these four e students differ in the grades compared to the average for the population. Remember that you'll need to calculate the population standard deviation first! Student Their Research Methods II Grades A 80 B 75 90 95 S8 D Question 3 1pts Indicate the level of risk used in psychology The level of risk is.01 O The level of risk is.5 The level of risk is .05 The level of risk is .1 Question 4 1 pts Determine the best statistical test to use Correlational test Critical value test e Z score test one-sample Z test 1 pts Question 8 Based on your answer to the previous question, the decision is to Reject the null hypothesis Fail to reject the null hypothesis 1 pts Question 9 Write up your results as you would see it in a results section of an empirical research paper: HTML Editor X x E B IUA A IE T 1 Paragraph PG 12pt I

Answer 1

Solution -3

if nothing is specified

alpha=0.05

so level of risk is 0.05

OPTION C

Solution-4

since population standard deviation is given it is

one sample z-test

Solution8:

Book1 Excel Tell me what you want to do... Adabala Naveenkumarvenkat Share File Home Insert Page Layout Formulas Data Review View fi КЗ3 Sensitivity: Not set Cantidential Public Intemal Restricted A C D F F G H J M N O 17 85 18 83 19 82 20 84 21 81 given sample 22 79 80 78 23 85 -AVERAGE 85 26 mean 96 27 93 28 93 29 88 30 31 population mean -AVERAGE( B1:B30) 84.4 32 population standard deviatic-STDEV.P(B1:B30) 33 7.01237 34 35 36 37 38 39 40 Sheet Sheet2 + 100% Ready Scroll Lock a:55 AM Type here to search S. х 6/28/2019 L.

z=85-84.4/7.01237/sqrt(30)

z=

0.468648

z crit at 95%=1.96

z stat<z crit

Fail to reject the null hypothesis

Solution8:

there is no sufficient statistical evidence at 5% level of significance to conclude that the 4 students differ in the grades compared to average of the population