Question

MECH3211- Stress Analysis Tutorial Assignment #6 Thursday, June 27, 2019 Student ID# Name: Problem 2: The Select the lightest-weight wide-flange beam from Appendix B that will safely support the loading. The allowable bending stress is aaltow 24 ksi and the allowable shear stress is Tallow 14 ksi. 6.75 kip/ft 12 kip 1.5 m 2 m m

Answer 1

(2 14b kik (dt ( tt ) C. l0ad W-G7s x 2X 3:28) 5m 5m- 2m 44.2935 KP RA 44.2935 Now dor cb" 아 beam RAt RB- 12 +W RAIRB= 12t u4.293S SFD (Kip) RA+RB =S6 2935 8.7645 20 7645 MMA-O (12x J.5)(Wx 4) Rex3= (12x1-5)+ (uu. 2935 x4) Rox3 r3.14675 kib-m Rs- GS.058 Kip 44.2935 -8.7645 1p RA BMD (Kib-m) In opporite dirm that from Bendiny We Com See dingrim moment at point B 's mari'mw m Benday mement u4.2935 X) 44.2935 Pip-m MB Mnar C/s at B CMitical Cs is So

NA NA for So Point p wiU be h wide Homze beam potnt wil b in P Ctnsin point) omd mar imw m tension Com forressiontaICnj maximum Cn'hcal Trms verse Shear shess at P mest away rem Nuehrad axis se So Stadeo Strcss + at p man bmaa YER for Syle aperatb max allow SAY=Sectisn medsluy % abaut * Mmax Callow trov S TE u4.2935 3.28) X12 24 Sxy SIN 7 72.60 35 in Spy )min 72.6635 in3

Now manimom absohute Shear shey et Point p Abs- 7max b)max 44.2935 X 3.281 X12 4 14 2x SAM Say 62.2829 n 3 Snx)min 62.2825 3 Shear Cn'ten'md bending Coitemd Sxx 72.6635 'n 3 max nyin Sapety by both) Requird Cross Sechion dor fulili this reguivement Sayndert So th W 21X 44 h = 20.7 in GS I'n O350 1n 13.0 in 2 Avca waight (l/) hn 81.6 tn 3 Say 4 84 3 Ixy=