Question

A ball is kicked at an angle of 25 degrees with an initial velocity of 40 m/s. What is the total time the ball was above the ground? Assume it lands at the same height as it was hit.

Answer 1

For projectile motion with angle of projection o and inti all velocity O, the y-component of velocity is Vy = Vesine - gt :. Y = Vasino) t -96% Now, time of flight of the projetike is the time when y=0 . Vo sino Lt) - gt² = 0 t=2&osing In this problem, o = 25° and vo= 40 m/s and we know g= 9.8 m/s² the total time the ball was above the ground is, t = 2x40x sin 25° t = - seconds 9.8 = 3.45 seconds