Question

Consider the following concrete retaining wall: 1.5ft La = 12° Sand: y = 115pcf 16ft d = 32° c=0 d = (2/3) Concrete: y = 1

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part Send Har 115 pcf a 2 C-o 5st 11565st Clayes 120 pcf ; qf=22°; c= poopsf BC = H Ja 12 1 ton lao = H 6.5 fosil H = 1:3816TAM ka - (050.00 sd - J costa - caste cosa + J costa-cose 0 =B1 = 39 = cos(13) Cos(11) - 1 (03160) - cos (39) cas(19) +cosciI achive force (fa) - to xx, x H²xka = x115x(20:3816.) 0397 3 7810.74 pounds (ft 9 pessive force (pp) = 5x115 x [ 20138198919! Section Pe=154,159 PCF 8591 2115 pcffor 059 Area(A) W=rxai al fom me = wl se) (ebist) lol point (1h-ft) 4705 7392.92 9x5 3:Eva Ev + Pa Sind sackve Evp = Ev + P p sind + Passive a=120 na pe cosa tra coso G = 6-793 vertical components of active concii) (m.) p = pp cosa xý = 69747-47 COSL12) X6-793 = 463439.6368 lb-ft-; Active case (Fs) overturning = EMR (mola - 914672 51Posive - Resultant force B-1360 K B=13ft Imer = PEP (1+) 9 min = (-60) | ă= {MR-(Molp Evp = 914679 -463439668 43353.31 =-5.73Imea o amin is for active case only fearable: B = 13 ft 2 mex, min = het in dit ) = 30475.98 + 6x1.16 13U 19 = 9344.306 + 185d a chove (Fs) Sliding = (Eve) tanes) + CQB+pé Pa cosa Øg = Bottom Soil 3300 =190; 8 - = 48 499 = 14.67% Cal = R x C = X 200possive conditions: sliding = 30475.98 ten [14:67) +13X13933+ 1379:18 7810.74 (8512 = 115 315 Sale for passive conditions CEE

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