Question

( ulat will eject electrons (i.e. the kinetic energy of the electrons after ejection is equal zero)? 4 (3pt) Calculate the de Broglie wavelength for the following: a. An electron moving at 5.31 x 106 m/s. b. A baseball thrown at a speed of 97 mph. The mass of this baseball is approximately 145 grams. c. A 175 lbs human being running at a speed of 2.2 km/hr. d. How does the de Broglie wavelength of the electron differ from the de Broglie wavelength of the human being? If their wavelengths differ, what can be said about their energies? Does this result make rational sense, and if so, explain.

Answer 1

-34 V = 5.31906 mis mass of electron = 9.1x10mling Ash 6.626 X10%.5 mu 91x103.1cm x 5.31x100 X= 237x10m 0.uun Imph = 43-363 m/ -34 6.626 X10 J-S Ib V=97 mph = 97 mph m=1459 = 0.145kg h = 6.626x10345.5 dah = 6.626 X10 "FJ zlostis long mv 0145169 x 43.363 m/s - © m=175 lbs = 175 lbs 0.454109 = 79.45 kg v= 2*2 km/h = 2.2km/hy * 0.278 m/s = 0.6188 mils 1 = 6.626 xro345.5 79.45kg x 0-6116mis ware length of é is very high comperd to ware length of human being. As wave Lengths are largely differed we can understand that é is moving in the found wave, but in case q human it is not observed CS Cams Debroglie Wale length is applicable to microscopic a particles . 1 Km/hr -35 -1- 36 x 10 m