Part 3 - Voltage doubler 9. What is the maximum DC voltage expected across Rl in...
RS Given that R2-40K, R5-10K, R6-10K, R7-10K, RL 5K, C 1-1 000uF, C3-. 1 uF, C4-1 000uF, C2-0pF and Vec=1 5V. Vcc C3 n RT Vin C1 vo Draw the DC model of this circuit. a. R6 RL Find the bias voltage at pin 3 of the op amp. b. ua741 R2 C4 Find the low-frequency cut-off of this circuit. c. acts like a short circuit? What is the input current at pin 2 of the op amp? e. f....
The circuit above is a Zener voltage regulator using D1N750 zener diode with Vz=4.7V: 1. Calculate the minimum value of E in order to have the voltage across RL regulated VL=Vz 2. Using Orcad PSpice schematics, simulate the circuit using bias point and find Iz, IL, Is and Vz (the circuit must have all voltages and currents values shown). 3. Using Orcad PSpice schematics, use DC sweep to vary RL from 200 ohm to 1000 ohm and plot VL (for...
For the amplifier circuits in Figs.3 and 7: a. Write an expression for the output voltage, vo, in terms of the resistor symbols and the input voltage, vin. ---For the first circuit (Fig. 3), the feedback resistor is the series combination of R2 and R3. Use both of these resistor symbols in your expression. -- For circuit 2 (Fig. 7), assume that vin = 5V and ignore potentiometer R1 and C3. b. Using resistor values and input voltage amplitudes, calculate...
a9a resistive load. Inductor 3-(35 pts) Design a converter that has an input voltage of 24 V DC and supplies 18 V DC to current is desired to be continuous and must not change more than 30 % of its average value voltage ripple must be lower than 2 %. Switching frequency is 10 kHz. a) Draw the circuit diagram. Calculate the duty ratio. Calculate values for 2 desired conditions of the inductor current and determine the value of the...
F LOpoint For the circuit shown in Figure 3 3. 1. Draw the DC equivalent circuit by opening caps and shorting inductors 2. Analyze the DC equivalent circuit as we have in previous labs (assume a region, analyze and check assumptions). Check your DC operating point using LT Spice. 3. Calculate the small signal parameters (transconductance, output resistance, input resistance) 4. Draw the AC equivalent circuit by shorting de voltage sources, opening dc current sources, shorting caps and opening inductors....
please I need details l and....Debate Club | Offic A) Theoretical Design Design a common emitter BJT amplifier with the following requirements: -Rin-10 K2, and Ro-45 ㏀ (Neglect the Early voltage Effect) Vo/Vsig- Gv-40 VIV or 32 dB " VCC-9 V V, IC-1mA, VCE-3.25V and β-100 RL-40 kQ, Rsige I ka, R 1-3R2, and C1-C2-1 μF Voc RC C2 R1 Rsig C1 RL R2 RE B) Verify your design using Orcad Capture Pspice by doing 1) AC sweep (frequency response):...
A common-emitter BJT amplificr is shown in Fig.8.1. Note the DC biasing values and the BJTsmall-signalmodel parameters from the class-signment #9 on DC Bia ing. Neglect the value of Rs in your calculations, k1 Rs-a k2: 1· Cal ulatethesmall-agalpannetas ofthe amplifi randcompletethecalculated valuesinTable8-1 Smalls-signal voltage gai, AVk Small-signal input resistance,k, Small-signaloutput resistance, Ro VW RC 2k C2 RB 570k Rs C1 1 10uP 0.1m 1 Vs CE RE 2k SINE(0 1mV 1kHz 0 0 00) tran 0 2ms 0 1us...
Problem 3 The periodic voltage source in the circuit shown in Figure P3 (a) has the waveform shown in Figure P3 (b). a) Derive the expression for Cn b) Find the values of the complex coefficients Co, C1, C1, C 2, C2, C3, C3, C4, and C4 for the input voltage vg, if V,-54 V and T-10π us c) Repeat b) for Vo. d) Use the complex coefficients found in c) to estimate the average power delivered to the 250...
The circuit 3-The circuit of problem # 2 is subjected to a small ac input by the signal generator. By neglecting the voltage drop across the coupling and bypass capacitors, determine the small signal voltage gain Vo/ Vì = Avi , input resistance Ri-vi / ii and the output resistance Ro external to R Avi= Ri= , Ro The accompanying circuit shows a 4-resistor biased JFET transistor Determine the values of Rp and Rs so that the Q-point is equal...
Voc Ri Rc C2 + RS G Q2N3904 RL Vout 2 R2 RE CE Rin Rout Cu B 1x B C o + V be : Cr 8m'be E VCC R R2 Rc RE RS RL С. Cz CE 12 V 8.2 kg 3.9 ko 6.3 k2 3.3 kΩ 3 ko 3.9 ko 10 uF 1uF 100 u Assume the 2N3904 has a 8 =100, Veron} = 0.7V, VA= 100V, C=100, C=13.9pF and Ce=8pF. Use the emission coefficient as n...