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QUESTION 3 COHM 2014 if our skater changes her radius of gyration from 1 m to 0.4 m, how much (percentage) does her angular i
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Answer #1

initial angular inertia = mr^2

= m*1^2 = m

Final angular inertia = m*0.4^2 = 0.16m

change in inertia = m - 0.16m = 0.84m

% change = 0.84m / m * 100 = 84 %

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