Question

Law A solid cylindrical conductor is supported by insulating disks on the axis of a conducting tube with outer radius Fe-6.35 cm and inner radius Ri,-4.95 Cm (Figure 1) The central conductor and the conducting tube carry equal currents of I 2.85 A in opposite directions. The currents are distributed uniformly over the cross sections of each conductor. What is the value of the magnetic field at a distance 5.93 cm from the axis of the conducting tube? Part C What is the value of the magnetic field at a distance r 5.93 cm from the axis of the conducting tube? Recall that IY = 4π × 10-7 T·m/A. Express your answer numerically in teslas. View Available Hint(s) Figure 1 of 1 Submit EVALUATE your answer Part D Complete previous part(s) Next > Provide Feedback

Answer 1

The area enclosed by the cylinder is, out 2 π (6.35x 10-2 ). π (4.95x 10-2 ) = 0.0102 m2 The area of enclosing cylinder within 4.75 cm A = ( π( 5.93x 10-2 )-) -( π(4.95x 10-2 )2 0.00335 m^ The current carried by the enclosing cylinder is, 0.00335 = (2.85) 0.0102 =0.93 A The net enclosed current is, = 2.85-0.93 = 1.91 A The required magnetic field is, 2m7 47×10")(1.91) 2n( 5.93× 10-2 = 6.44×10-6 T