![Explain the following observations: (a) Phenol is soluble in aqueous solution of sodium hydroxide but cyclohexanol is not. LO: 8.6(b)i reacts with iodine in aqueous solution of sodium hydroxide to produce yellow ILO: 8.5(d)] precipitate but 1-propanol does not. ompound Y, CHeO, is insoluble in water but dissolves in dilute aqueous NaOH. When Y is treated [LO: 8.2 LO: 8.6(b)ii & ii LO: 8.6(b) li with bromine water, it is converted rapidly into a compound with molecular formula Cr. (a) Suggest the structural formula of Y b) Write all the equations involved. (c) Give one confirmatory test for Y](http://img.homeworklib.com/questions/5c8deab0-9456-11ea-a1a6-7f2f4d44edb6.png?x-oss-process=image/resize,w_560)
Homework Answers
17 a) Phenol is soluble in NaOH because it form phenoxide ion with NaOH which is soluble in NaOH but cyclohexanol is not much acidic and thus less soluble in NaOH.
b) Only methyl carbonyl give yellow precipitate with iodine in NaOH and ethanol easily oxidize into ethanal in presence of NaOH and iodine but propanal (on oxidation of propanol) does not contain methyl carbonyl and thus don't give yellow precipitate.
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I was wondering if someone could help me with problems on my
test my teacher allows me to correct the wrong ones then give them
back for half credit. Along with the correct answer for each I’d
like to know why the answer I chose is wrong what is the correct
answer and why it is the correct answer. The marked red problems
are the incorrect problems.
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