Consider a sampling distribution with p=0.09 and samples of size n each. Using the appropriate formulas, find the mean and the standard deviation of the sampling distribution of the sample proportion.
a. For a random sample of size n=4000.
b. For a random sample of size n=1000.
c. For a random sample of size n=250.
A)
As per the given information
mean μp^=p= 0.09
random sample size n=4000
standard deviation σp^ = Sqrt( p (1-p) /n)
=sqrt( 0.09 * 0.91 / 4000)
=0.004524
B)
mean μp^=p= 0.09
random sample size n=1000
standard deviation σp^ = Sqrt( p (1-p) /n)
=sqrt( 0.09 * 0.91 / 1000)
=0.00904
C)
mean μp^=p= 0.09
random sample size n=250
standard deviation σp^ = Sqrt( p (1-p) /n)
=sqrt( 0.09 * 0.91 / 250)
=0.01809
Consider a sampling distribution with p=0.09 and samples of size n each. Using the appropriate formulas,...
Consider a sampling distribution with p=0.09 and samples of size n each. using the appropriate formulas, find the mean and the standard deviation of the sampling distribution of the sample proportion of the following parts: A)for random sample of size n=5000 B)for random sample of size n=1000 C)for random sample of size n=500
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