Question

3. Given the following simple distillation column system, Stream 2 Faw [kg water/hr] Fis Ikg solute/hr] Stream 1 Fiw kg water/hr] Fis kg solute/hr] Stream 3 Fsw [kg water/hr] Fzs Ikg solute/hr] And the following information about the system: 1. The total flow rate of the feed (ie. Stream 1) is 2000 kg/hr. II. 90% of the water entering in the feed exits in stream 3. III. Stream 2 will be 75 wt% solute. IV. Stream 2 has a total flow rate of 600 kg/hr. Your colleague has already written down 2 component balance equations and has written equations to capture the information given in items I and IV above: Fiw + F1s = 2000 iw - Fw - Fw = 0 Fis - Fas - F3s = 0 F2W + Fus = 600 Complete the following tasks: a. Write down two additional valid linear equations to capture the information given by additional information II and III above. b. Write the A matrix & b vector to describe this problem in Ax=b form. c. Use MATLAB to solve this system of equations. Be sure to copy the command line inputs and outputs used to complete the step into a WORD document and include that material in your PDF answers to this homework. d. Check your answer by solving this problem by hand. Note you do not have to solve it using matrix methods, you can solve it algebraically.

Answer 1

2015 -9 Ebram Faw (kg, Ines) Fas (uglas) Sfuam firo nglus Fis (kg/us) alwam (3) F30 (kglias F3 luglwer) hiwt fis = 2000 - fino - frio - F30 0 - fis - Fas - fzs._=0 — ..F24_t fos = 600_ F3W 0.gfiw-o given Fw =907 Fas = 0.75 X600 = 450 46 & given In stream 2, 75t is salute i o o o o 7 fino 2000 Do 0 -1 0 -1 | Floo loo Loo | Fasi -10. 90_O O ; IO II iFzio To o o o olfs J 600 1 y = + filo fis | 2210 у - р Ало99 A = Loooo LLO:.- 10-10 Lo 0 -1 0-1 00 i -0.g ooolo to oo Tool es Scanned with 12S Blo uro fs CamScanner

..*510 - 0.3445 M 0 d from on @ fos = 40 e llom egna_fan_ 600_-62S = _150 on ko to .. ogn @ + eon t o Chiw #fis) - Cair tfes) - lfzwa tf35) = 0 1.8000 - 600 fz1o #138- fgua + 65 = 1400 378) from ano foco = 0.9 fino Gom 80 foom eq n 26 Ella - 150 - 0.9 Fico = 0 Oolfiw = 150 - Thio = 1500) F3w = 0.gx fic S z of9 X 1100 3 1350 how 2350 from egh h s = 1900-F30 = 1400-1350 (50) I from ean ③ Fis - 450 :fis 50 20 500 ao final results in alt aru in Ky iner fin = 1500, fas =410, fs = 50 Eis = 500 F2W = 150 fsw=1350 S

..*510 - 0.3445 M 0 d from on @ fos = 40 e llom egna_fan_ 600_-62S = _150 on ko to .. ogn @ + eon t o Chiw #fis) - Cair tfes) - lfzwa tf35) = 0 1.8000 - 600 fz1o #138- fgua + 65 = 1400 378) from ano foco = 0.9 fino Gom 80 foom eq n 26 Ella - 150 - 0.9 Fico = 0 Oolfiw = 150 - Thio = 1500) F3w = 0.gx fic S z of9 X 1100 3 1350 how 2350 from egh h s = 1900-F30 = 1400-1350 (50) I from ean ③ Fis - 450 :fis 50 20 500 ao final results in alt aru in Ky iner fin = 1500, fas =410, fs = 50 Eis = 500 F2W = 150 fsw=1350 S