Find zα/2 for each of the following confidence levels used in estimating the population proportion.
Round your answers to 3 decimal places.)
zα/2 | ||
a. | 90% | |
b. | 98% | |
c. | 85% | |
d. | 95% | |
e. | 99% | |
Find zα/2 for each of the following confidence levels used in estimating the population proportion. Round...
confidence level and sample data to find confidence interval
for estimating a population round your answer to the same number of
decimal places as a sample
Question 2 2 pts Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 90% confidence; n 390, x-146
1. Find the critical value zα/2 that corresponds to a 94% confidence level. Round your answer to two decimal places. 2. The following confidence interval is obtained for a population proportion, p: 0.273 < p < 0.592. Use these confidence interval limits to find the sample proportion . Round your answer to three decimal places. 0.433 3. Find the minimum sample size : How many commuters must be randomly selected to estimate the mean driving time μ of Chicago commuters?...
Constructing Confidence Intervals, Part 1: Estimating Proportion
Assume that a sample is used to estimate a population proportion p.
Find the margin of error E that corresponds to the given statistics
and confidence level: In a random sample of 200 college students,
110 had part-time jobs. Find the margin of error for the 98%
confidence interval used to estimate, for the entire population of
college students, the percentage who have part-time jobs. Round
your answer to three decimal places.
Please...
Find a confidence interval for μ assuming that each sample is from a normal population. (Round the value of t to 3 decimal places and your final answers to 2 decimal places.) (a) x⎯⎯ x ¯ = 25, s = 5, n = 7, 90 percent confidence. The 90% confidence interval is to (b) x⎯⎯ x ¯ = 50, s = 4, n = 19, 99 percent confidence. The 99% confidence interval is to (c) x⎯⎯ x ¯ = 121,...
need help with this one
Find the confidence interval for estimating the population proportion for parts (a) through (c). a. 92.5% confidence level; n = 600; P=0.20 b. 99% confidence level; n = 140; p = 0.04 C. Q=0.09; n = 375; p=0.90 Click the icon to view the standard normal table of the cumulative distribution function. a. The confidence interval is <P (Round to four decimal places as needed.) b. The confidence interval is <p<. (Round to four decimal...
Supplementary Problem 8.50 Use the following information to compute the confidence interval for the population proportion. a. n = 715 and x = 329, with 95% confidence b. n = 284 and p = .71, with 90% confidence c. n = 1250 and p = .48, with 95% confidence d. n = 457 and x = 270, with 98% confidence (Round your answers to 4 decimal places.) VI VI VI VI VI VI VI VI
Find the confidence interval for estimating the population proportion for parts (a) through ) Think carotary about what the z vates we in each part, having in mind that confidence level = -- and we z value is a vete leaving a probability in the right tal or ne 10.1) darbution a 90% confidence levet n-650: 0-0.30 6.95% confidence levet 220-002 -0.03;305 P0.50 Cine icon to view the standard nomor title of the curve debution function a. The confidence is...
For the following sample sizes and confidence levels, find the t-values suitable for building confidence intervals: a) n = 15; 90%. b) n = 6; 95%. c) n = 19; 99%. d) n = 25; 98%. e) n = 10; 99%. f) n = 41; 90%.
I recommend that you practice using the standard Normal tables to calculate zα/2 and tα/2 . Costs are rising for all kinds of health care. The mean monthly rent at assisted-living facilities was recently reported to have increased 15% over the last five years. A recent random sample of 120 observations reported a sample mean of $3563. Assume that past studies have informed us that the population standard deviation is $650. For this problem, round your answers to 2 digits...
Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. In a clinical test with 1600 subjects, 800 showed improvement from the treatment. Find the margin of error for the 99% confidence interval used to estimate the population proportion. a. 0.0322 b. 0.0184 c. 0.0245 d. 0.0282 ON