Question

A weight is added to a piston so that the volume of the gas inside the container is reduced from 3.0 L to 1.0 L at a constant temperature. How much heat do you need to add to the system if you want to increase the volume back to 3.0 L at this new pressure? Assume an ideal gas and an initial pressure of 1.0 atm

Answer 1

2? 34 4 Initial Pressure at latm Ideal Gas PV = P₂ V₂ = nRT. Samuvalue. P2 = x 3 atm. W12 = (201325) (Bc.) ln(43) J W2 = - 333.951 J. Pressure applied by weight At stage 2. Tot Patmospheric Pweight. 917 P₂=3 ahm Pweight & Patmosprwin = P2 Pweight = 2 ahm.

P( VYD Now heat is applied Means Piston will move up Against const Pressure of Palm & Pweight = 3 atm. - W₂ = 3(3-1) (101325) J. Parm 1000 latm=101325 Pa Wqp = 607.95 J V For Process. (1 →2) AU=Q 12 - Wizi AU=o const Temperature. SS

AU=0 const Temperature. 812 = W 12 = -333.9515 Overall Prouss wanitaris 2 1 AU = EQ - EW ! AU=0 (As it Reforended to its Initial state). O = Q, 2+Q₂ ( Wigt Way). 0 = 8 + 9, -(-333.45 146 01:45) Q 21 = 607.955
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