Question

Complete the following table for refrigerant-134a; TF Ppsia h Btu/Ibm 64 Phase Description 70 0.7 70 180 128.77 110

Answer 1

P= 7opski, h= 64 Bullbm form saturated R134a - Pressuse tables fro p=7oppia hf = 30.862 Bullbm, bg = 111.25 Btullom nfchchg :Saturated liquid vapouro mixterne. T= Tsat @ Topsia T = 58.300F h= hf + X( hg-hf) 64 = 30.862+ X(111.25 – 30.862) bc= 0.412 T=20°F, 2=0,7 x=0.7 -- saturated liquido vapour mixture Pa psat @ 28 F P: 33.147 poia] h= hfta hfg @ 28F h= 19.459+0.7687.541) Th = 79.827 Petul Llom © T=10° F, P = 70 poid For T= 10of Psal-= 26.646 psia] - Po Psati. Compressed lighed hr hf @ 100f th= 15.308 Stul (born ☺ P=180 psiq, h=128.77 Btullom. For P=180psia, hg= 117.98 Btullbm S ns hg .super heated vapour

from super heated tabler, P= 180 psia, h=128.77 stallbm IT=160°F OP=1105; X=1 i Satworted vapour] - Pz Psat @ 119F [P= 161.04 psia , ha hg @ 1BE Th= 115.96 Btullom Phase Descriphion TOEP (psià) h (Btullom) 0.412 Saturated liquid vapour mixture 58.30 70 64 0:7 20 79.827 33.447 Saturated liquid vapocro molixturae, Comproessed lifcich 15308 saterrated vapour TIO 160 THO 70 180 I 161.04 | 128-77 10 Saturated Vapour 115.96 lo