Question

Q5 is D, Q6 is B. Please answer step-by-step.

5. What mass of 12 can be produced from aqueous KI if a current of 15 A is applied for 1.0 hour? 12 + 2e → 21" ; E° = 0.54 V 2H2O + 2e- → H2 + 20H"; E° = -0.83V A) 36 g B) 0.020 g C) 2.6 g D) 71 g E) 12 cannot be produced under these conditions Electrolysis of an alkaline earth metal chloride using a current of 5.00 A for 748 seconds deposits 0.471 g of metal at the cathode. What is the identity of the alkaline earth metal chloride? A) CaCl2 B) MgCl2 C) CrCl2 D) CdCl2 E) TiCl2

Answer 1

solution :- 6 i = 15 A t=lhow=60x6os 12tzé zi Equivalent mass all2= molesmans 2 = 254 2 = 127 - E Accordig to feraday's 1st law, mass de fosited (y) = {.lt 96500 =) m= 127x15x60x60 96500 m=71.0679) Answer: D) ng 6 i is.oampere t= 748 Seconds mars deported, m=0.4719 м-1 +2 Ms - Alicalere earth metal Let molar mars of metal =M ² quivalent mars, E=m

: using feraday's 184 Low, - M= E-lit 96500 =) 0.471= Mx5x748 27 96500 M = 0.47182496500 5X748 7 M = 24-30 g/mol This in the molar massal Magnesium (mg Answer: B) Mg la)