Question

a.

Consider the follow equations: A+B →D AH° = -70.0 kJ E +2 F → A AH° = -20.0 kJ C + E +2D AH° = -300.0 kJ Calculate the AHⓇ for the reaction: C+2 F → 3 A +2 B

b.

Answer 1

D By Hess's we law, find can oth of new teachiory from previous reactions at value by performs Gasic algebric operations. ① A + B ) D oH =-7000 kJ © E+2F 3 A on' = - 20.065 * c E+20 JH = - 300.0 kJ I Fine oht or ct of 730+2B By pes froming -20 we can O le ca a B get in products. By Just © ® we reaction. Pesforsm , -20 + in - can get a 2F ④ + 6 7

' Z'D > 2A + 2B OH'= -26-70.0KJ) 24+ 2.8 Et af ZA ONE t - - 20.0 kJ LEHED SHE-300.0 kj ct of » 3A + 2B ..OH = [2(-70.0K5+ [-20.0 ks] + [ 3000 ks] = 140 kJ - 20.0 kJ-300. okt = -180.0 kJ :: Ah) $6° = F-180.0 KT) B Find Dt f =) Grm © we can By performing - reactants. By Performing ☺ m in products get f in ☺ we cant get G,

- Pest xmi 0+ (0 + ® . TA + B FAT CHF EEA G moke 100.0 ko o st' =-E 300.0 KJ) e om te on OH = - 1500kg - PTF Gtm : OH = 100.0*5+ [16360.067)+ [150.0kn) = 100.0 k 5+ C300.0%) + (-15110ka = 250.0 kJ .: Ans)'.- Die =[ 250.0 KJ)